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ale4655 [162]
2 years ago
8

If 40 percent of a movie ticket costs $5.00 what is 20 percent of the cost of two tickets

Mathematics
1 answer:
Nikolay [14]2 years ago
8 0
<u>Find cost of a ticket:</u>

40% = $5.00

1% =  $5 ÷ 40 = 0.125

100% = 0.125 x 100 = $12.50

The cost of a ticket is $12.50


<u>Find 20% of two tickets:</u>

Two tickets cost $12.50 x 2 = $25

20% of $25 = 0.25 x $25 = $5

Answer: 20% of two tickets cost $5
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egoroff_w [7]

Answer:

She will most likely to choose a dog than a cat

Step-by-step explanation:

8 0
2 years ago
Find the supplement of the complement of 76°
Setler [38]
I hope this helps you




supplement ? +76=90 ?= 14



complement ?+76=180 ?= 104
8 0
2 years ago
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hakeem's frog made three quick jumps. the first was 1 meter. the second jump was 85 centimeters. The third jump was 400 millimet
Paha777 [63]

To add the jumps made by three frogs, you have to convert the units into a specific unit for uniformity. Let us use meter. For every 1 meter, there are 100 centimeter and 1000 millimeters. Divide 85 by 100 and 400 by 1000.

 

<span>1 + 85/100 + 400/1000 = 2.25 meters</span>

5 0
2 years ago
Determine the number of proper subsets contained in S if S = {x|x is an even, negative integer and x &gt; -27}
zzz [600]
First, lets determine |S| (the number of elements in S).

We can see that the negative even integers that are between -27 and 0 are: -24, -22, -20, -18, -16, -14, -12, -10, -8, -6, -4, and -2.
This means |S|=13.

A proper subset of S is can't be S itself, this means the a proper subset of S can't have 13 elements.

Given that re-arranging the elements of any set doesn't yield a different set, we use combinations (binomial coefficients) to get the number of subsets in a particular set.

The number of subsets of S with 1 element are given by (^{13}_{1}) (which means 13 combine 1), in the same way the number of subsets with 2 elements is given by (^{13}_{2}) and so forth until reaching the number of subsets with 12 elements.

The previous statement can be written as:
\Sigma^{12}_{k=0}(^{13}_{k})

In the previous summation we also included the empty subset, which is always a proper subset of S.

So \Sigma^{12}_{k=0}(^{13}_{k}) is an acceptable answer, but we can simplify it. 
The following statement is true (it can be easily proven):
\Sigma^{n}_{k=0}(^{n}_{k})=2^n

From our previous discussion, this means that the number of subsets of any arbitrary set S is equal to 2^{|S|}.
This means that the number of proper subsets (which is the number of subset minus the set itself, for finite subsets) is equal to 2^{|S|}-1.

So, the answer is:
\Sigma^{12}_{k=0}(^{13}_{k})=2^{13}-1=8192-1=8191

There are 8191 proper subsets of S.
8 0
2 years ago
Aramis is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli
Mariulka [41]

Answer:

The antenna should be place 0.75 inches above the vertex.

Step-by-step explanation:

We have the equation of the parabola:

(x-4)²=3(y-3)

The general equation of the parabola is:

(x-x₀)²=4p(y-y₀)

where:

(x₀,y₀) is the vertex of the parabola

p is the focus of the parabola

Hence,

The vertex of the parabola is (4,3)

The focus of the parabola is given by:

3=4p\\ p=\frac{3}{4}\\ p=0.75

Then, we have to shift the antenna towards the focus point. The focus point would be:

(x₀,y₀+p)=(4,3+0.75)= (4,3.75)

The directrix of the parabola is:

y=y₀-p

y=3-.75=2.25

A graph of the parabola is attached, with its focus point (4.3.75) and its directrix (y = 2.25)

8 0
2 years ago
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