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ale4655 [162]
1 year ago
8

If 40 percent of a movie ticket costs $5.00 what is 20 percent of the cost of two tickets

Mathematics
1 answer:
Nikolay [14]1 year ago
8 0
<u>Find cost of a ticket:</u>

40% = $5.00

1% =  $5 ÷ 40 = 0.125

100% = 0.125 x 100 = $12.50

The cost of a ticket is $12.50


<u>Find 20% of two tickets:</u>

Two tickets cost $12.50 x 2 = $25

20% of $25 = 0.25 x $25 = $5

Answer: 20% of two tickets cost $5
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Amanda bought g gallons of paint for $16.55 per gallon and t pints of paint thinner for $5.97 per pint. Write an expression to r
Neporo4naja [7]

Answer:

total \ cost =16.55(8) +5.97(3)=150.31

Step-by-step explanation:

Amanda bought g gallons of paint for $16.55 per gallon and t pints of paint thinner for $5.97 per pint

Total amount = rate per gallon times gallons + rate per pint times  pints

total amount =16.55 g +5.97 t

amanda bought 8 gallons of paint and 3 pints of paint thinner

g=8 and t=3, substitute the values and find total cost

total \ cost =16.55(8) +5.97(3)=150.31

3 0
2 years ago
Select the correct answer from each drop-down menu. Polygon ABCDE rotates 45° clockwise about point F to form polygon FGHIJ, sho
Umnica [9.8K]

Answer and Step-by-step explanation:

As it is mentoned in the question

Polygon ABCDE rotates around point F in clockwise direction to create polygon FGHIJ

And as we can see in the figure that

So we conclude that

A = F ⇒ 117°

B = G ⇒ 90°

C = H ⇒ 127°

D = I ⇒ 90°

E = J ⇒ 117°

Therefore this is the answer and the same is to be considered

6 0
1 year ago
Have you ever been frustrated because you could not get a container of some sort to release the last bit of its contents? The ar
snow_tiger [21]

Answer:

Yes. There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Step-by-step explanation:

The sample of the remaining toothpaste is: [.53, .65, .46, .50, .37].

This sample has a size n=5, a mean M=0.502 and standard deviation s=0.102.

M=\dfrac{1}{5}\sum_{i=1}^{5}(0.53+0.65+0.46+0.5+0.37)\\\\\\ M=\dfrac{2.51}{5}=0.502

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.53-(0.502))^2+...+(0.37-(0.502))^2]}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.001)+(0.022)+(0.002)+(0)+(0.017)]}\\\\\\            s=\sqrt{\dfrac{0.04188}{4}}=\sqrt{0.01047}\\\\\\s=0.102

The 10% of the advertised content is:

0.10\cdot 6.0\;oz=0.6\:oz

Hypothesis test for the population mean:

The claim is that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Then, the null and alternative hypothesis are:

H_0: \mu=0.6\\\\H_a:\mu< 0.6

The significance level is 0.05.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.102}{\sqrt{5}}=0.046

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.502-0.6}{0.046}=\dfrac{-0.098}{0.046}=-2.148

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-2.148, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

7 0
2 years ago
Solve the following linear program using the graphical solution procedure: Max 5A + 5B s.t. 1A lessthanorequalto 100 1B lessthan
earnstyle [38]
<h2>Answer:</h2>
  • The optimal solution to the given linear programming problem exist at (100,50)
  • and the optimal solution is:  5A+5B= 750
<h2>Step-by-step explanation:</h2>

We are given  a system of linear programming problem as follows:

   Max 5A + 5B

s.t.        A ≤ 100---------------(1)

            B ≤ 80-------------(2)

          2A+4B ≤400-------------(3)

which is given by:

            A+2B ≤ 200

and   A,B≥0

This means that the solution to this LPP  will lie in the first quadrant.

( Since, both the variables A and B are greater than or equal to zero)

Now, we consider that A is represented by the  x axis and B by y-axis.

We know that the optimal solution always exist at the boundary point.

Hence, by plotting these inequalities in the graph we get the boundary points as:

(0,0) , (0,80) , (100,0) , (100,50) and (40,80)

Now, we will check at which boundary point the optimal function is maximized .

   Point        Value of optimal function( 5A+5B)

    (0,0)                           0

   (0,80)                         400

   (100,0)                        500

  (100,50)                       750

   (40,80)                        600

The maximum value is obtained at (100,50).

and the value of the optimal solution is:  750

5 0
2 years ago
Now evaluate f(x) = 2x4 - 4x3-11x2+3x-6 for x=-2 f (-2) =
bija089 [108]
f(x)=2x^4-4x^3-11x^2+3x-6\\\\f(-2)=2\cdot(-2)^4-4\cdot(-2)^3-11\cdot(-2)^2+3\cdot(-2)-6\\\\f(-2)=2\cdot16-4\cdot(-8)-11\cdot4+3\cdot(-2)-6\\\\f(-2)=32+32-44-6-6=8
4 0
2 years ago
Read 2 more answers
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