Given f(n+1) =-2f(n)
here f(n) =f(1) = -1.5
f(n+1) =f(2) = -2 * -1.5 = 3
Answer:
XY 
Represent a distance
√
Represent a segment
√
Represent a numerical value
√
Represent a geometric figure √
Can be found by applying the ruler postulate
√
Can be be duplicated with a compass and a straight edge √
Step-by-step explanation:
The difference between XY and
are that the points XY represents the distance between two points having a numerical value whose value can be found by using a ruler to find difference in the numbers on the ruler that coincides with the points, while
Well you are look at a 3d image here
so if area is length times width then we need to find the area of every side of the cabinet and add it up
11/3 on the calculator is 3.66666667 sooooo....
top: 3 x 11/3 = 11
side 1: 3 x 6 = 18
side 2: 3 x 6 = 18
front: 6 x 11/3 = 22
back: 6 x 11/3 = 22
so we have all of our measurements:)
now we just add them up together.
11+18+18+22+22= 91!!
so Frans would have to paint 91 square inches of that cabinet:) hope i helped
We have to find how the chess player can move a knight from one location to another.
Also we have to remember that the bottom - left square is labelled ( 1 , 1 ).
First he wants to move a knight from ( 3 , 2 ) to ( 5 , 1 ).
Answer: 2 squares left, 1 square down.
Then he wants to move it from ( 5 , 1 ) to ( 6 , 3 ).
Answer: 2 squares right, 2 squares up, 1 square left.
Answer:
The value of x that gives the maximum transmission is 1/√e ≅0.607
Step-by-step explanation:
Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

We need to equalize f' to 0
- k*(2x ln(1/x) - x) = 0 -------- We send k dividing to the other side
- 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
- 2x ln(1/x) = x -- Now, we send 2x dividing (note that x>0, so we can divide)
- ln(1/x) = x/2x = 1/2 ------- we send the natural logarithm as exp
- 1/x = e^(1/2)
- x = 1/e^(1/2) = 1/√e ≅ 0.607
Thus, the value of x that gives the maximum transmission is 1/√e.