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Hitman42 [59]
2 years ago
10

A kilogram is about 2.2pounds. A cube of water 30cm on edge weighs about how many pounds?

Mathematics
1 answer:
steposvetlana [31]2 years ago
4 0
It weighs about 2 pounds. hope this helps!!!
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Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?
sergeinik [125]

Solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

(\sqrt[3]{8})^x

Solving:

We know 8= 2x2x2= 2^3

and \sqrt[3]{x}=x^{\frac{1}{3}}

Applying these rules:

=((2^3)^{\frac{1}{3}})^x

=(2^{\frac{3}{3}})^x\\

=2^x

So, solving  RootIndex 3 StartRoot 8 EndRoot Superscript x we get =2^x

Keywords: Radical Expression

Learn more about Radical Expression at:

  • brainly.com/question/7153188
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8 0
2 years ago
Use what you know about translations of functions to analyze the graph of the function f(x) = (0.5)x−5 + 8. You may wish to grap
IrinaVladis [17]

Answer:

The Translation is 5 units to the right and 8 units up

Step-by-step explanation:

* Lets talk about some transformation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

∵ The parent function is y = (0.5)^x

∵ f(x) = (0.5)^x - 5 + 8 after translation

- The x in the first function is (x - 5) in the second function

∴ There is a horizontal translation to the right 5 units

- the first function is (0.5)^x in the second function y = (0.5)^x - 5 + 8

∴ There is a vertical translation up 8 units

* The Translation is 5 units to the right and 8 units up

- Look to the attached graph to more understand

- The purple graph is y = (0.5)^x

- The black graph is f(x) = (0.5)^x-5 + 8

- To check the answer take a point from the y = (0.5)^x as (0 , 1), the

 image of this point on f(x) is (5 , 9)

-The point (0 , 1) is shifted 5 units to the right and 8 units up

∴ Its x- coordinate move from 0 to 5, y- coordinate move from 1 to 9

5 0
2 years ago
Read 2 more answers
Ruby is visiting a wildlife center to gather information for her term paper. The center has a circular pond with a diameter of 2
Anton [14]
Well , the diameter means a straight line passing from side to side through the center of a body or figure, especially a circle or sphere. The area means what the extent or measurement of a surface or piece of land. So area means inside so all you need to do is  just to divide each side by knowing what 20/4 is and that = 5 meters
5 0
1 year ago
Which equation is the inverse of y = 100 – x2?
aleksandr82 [10.1K]
The function f be described by y=100- x^{2}

The graph of this function, is the graph of the parent function x^{2}, which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached. 


A function has an inverse only if it is decreasing or increasing.


So we must divide the following cases for which the inverses exist:

i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus, 

f(g(x))=x\\\\ 100-[g(x)]^2=x\\\\g^2(x)=100-x\\\\g(x)= \mp\sqrt{100-x}



so each of - and + cases, are the inverses of 


i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


At this point, recall that the domain of a function, is the range of it's inverse function, 

and the range of the function, is the domain of the inverse function.

thus, 

the range of \sqrt{100-x}, which is [0,infinity) is the domain of 

i) y=100- x^{2} with domain [0,infinity)



So our answer is:

inverse of i) y=100- x^{2} with domain (-infinity, 0] is -\sqrt{100-x}


and the inverse of ii) y=100- x^{2} with domain [0, infinity) is 

\sqrt{100-x}

4 0
2 years ago
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Rembrandt framed his masterpiece. The painting by itself is a rectangle with length 20 \text{ cm}20 cm20, start text, space, c,
mojhsa [17]

Answer:

Step-by-step explanation:84% of a contractor’s jobs involves electrical work. 75% of a contractor’s jobs involve plumbing work. Of the jobs that involve plumbing, 90% of the jobs also involves electrical work. Let E = jobs involving electrical work L = jobs involving plumbing work Suppose one of the contractor’s jobs is randomly selected. Using the sixth Excel worksheet, a) Find P(E). 0.84 b) Find P(L). 0.75 c) In words, what does E | L mean? d) Find P(E | L). e) Find P(E and L). f) Are E and L independent events? Why or why not? g) Find P(E or L). h) Are E and L mutually exclusive? Why or why not

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1 year ago
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