Let x represent the number of type A table and y represent the number of type B tables.
Minimize: C = 265x + 100y
Subject to: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1
From, the graph the corner points are (20, 20), (39, 1), (30, 1)
For (20, 20): C = 265(20) + 100(20) = $7,300
For (39, 1): C = 265(39) + 100 = $10,435
For (30, 1): C = 265(30) + 100 = $8,050
Therefore, for minimum cost, 20 of type A and 20 of type B should be ordered.
There would be 20 ounces of juice in a container in 6 seconds.
Hope This Helps!
Answer:
total money=rupees 50
3/5 of 50= rupees 30
money he spent = rupees 30
money he's left with =50-30=20
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-4 = 8m + 18n
-18n = 8m + 4
/-18 /-18 /-18
n = 8m/-18 + 4/-18
I'm not sure so yeah
Answer:
The Answer is: The first number is -70 and the second number is -68.
Step-by-step explanation:
Let f = first number and s = second number.
The sum of both is -138:
f + s = -138
The difference is -2
f - s = -2
Solve for f:
f = -2 + s
f = s - 2
Substitute:
s - 2 + s = -138
2s = -136
s = -68, the second number
Solve for f:
f = s - 2
f = -68 - 2 = -70, the first number
Proof:
f + s = -138
-68 + (-70) = -138
-138 = -138
Then:
f - s = -2
-70 - (-68) = -2
-70 + 68 = -2
-2 = -2
Hope this helps! Have an Awesome Day!! :-)
