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1 year ago

Thomas graphed the line that represents the equation y=34x.

Mathematics

1 answer:

zloy xaker [14]1 year ago

5 0

Answer:

The ordered pairs represent points on the line are

(4, 3) ⇒ C

(2, $\frac{3}{2}$ ) ⇒ D

(-8, -6) ⇒ E

Step-by-step explanation:

To find the ordered pairs represent points on the line, substitute x by the x-coordinate of each point, if the value of y equals the y-coordinate of the point, then the point is on the line.

∵ The equation is y = $\frac{3}{4}$ x

∵ The ordered pair is (8, $\frac{1}{6}$ )

→ Substitute x by 8

∴ y = $\frac{3}{4}$ (8)

∴ y = 6

∵ The value of y does not equal the y-coordinate of the ordered pair

∴ The ordered pair (8, $\frac{1}{6}$ ) does not represent a point on the line

∵ The ordered pair is ( $\frac{-2}{3}$ , $\frac{1}{2}$ )

→ Substitute x by $\frac{-2}{3}$

∴ y = $\frac{3}{4}$ ( $\frac{-2}{3}$ )

∴ y = $\frac{-1}{2}$

∵ The value of y does not equal the y-coordinate of the ordered pair

∴ The ordered pair ( $\frac{-2}{3}$ , $\frac{1}{2}$ ) does not represent a point on the line

∵ The ordered pair is (4, 3 )

→ Substitute x by 4

∴ y = $\frac{3}{4}$ (4)

∴ y = 3

∵ The value of y equal the y-coordinate of the ordered pair

∴ The ordered pair (4, 3) represents a point on the line

∵ The ordered pair is (2, $\frac{3}{2}$ )

→ Substitute x by 2

∴ y = $\frac{3}{4}$ (2)

∴ y = $\frac{3}{2}$

∵ The value of y equal the y-coordinate of the ordered pair

∴ The ordered pair (2, $\frac{3}{2}$ ) represents a point on the line

∵ The ordered pair is (-8, -6 )

→ Substitute x by -8

∴ y = $\frac{3}{4}$ (-8)

∴ y = -6

∵ The value of y equal the y-coordinate of the ordered pair

∴ The ordered pair (-8, -6) represents a point on the line

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Ahat [919]

Answer:

312 ft

Step-by-step explanation:

The steps are as follows :

1. The problem can be described as an equation

$x + \frac{1}{2}x + \frac{1}{8}x = 312$

2. Convert all values on the left side into their equivalent fractional values

$\frac{8}{8}x + \frac{4}{8}x + \frac{1}{8} x = 312$

3. Combine like terms

$\frac{13}{8} x = 312$

4. Multiply both sides by the reciprocal of 13/8 to isolate variable X

$concept \: \: \: ({ \frac{8}{13} \times \frac{13}{8} }) = 1$

$\frac{8}{13} \times \frac{13}{8}x = 312 \: \times \frac{8}{13}$

5. Simplify

$x = 192$

6. Check answer by using it in the original equation

$(192) + \frac{1}{2}(192) + \frac{1}{8} (192) = 312$

4 0

2 years ago

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

8 0

2 years ago

What is the probability of selection for any man in a proportionate random sample, where a sample of 100 will be drawn from a po

kolbaska11 [484]

Working Principle: Stratified Random Sampling

nx = (Nx/N)*n

where:
nx = sample size for stratum x
Nx = population size for stratum x
N = total population size
n = total sample size

Given:

Nx = 100
N = 1000
n = 0.5*(1000) = 500

Required: Probability of Man to be selected

Solution:

nx = (Nx/N)*n
nx = (100/1000)*500 = 50 men

ny = (Nx/N)*n
ny = (100/1000)*500 = 50 women

Probability of Man to be selected = nx/(nx + ny)*100 = 50/(50+50)*100 = 50%

ANSWER: 50%

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2 years ago

Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t

Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable X is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable X follows an Exponential distribution with mean, μ = 4 minutes.

The probability density function of X is:

$f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0$

The parameter of the exponential distribution is:

$\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25$

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx$

$=0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821$

Thus, the probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

3 0

2 years ago

Taylor has a $30 gift card that she can spend at the store. She has already bought a $9 picture frame, and she wants to buy $3 j

Lorico [155]

Answer:

Step-by-step explanation:

total is 30

spent is $9

this is total money minus the amount of the picture frame

30-9

21 divide by 3

the total sum of journals bought was 9

7 0

2 years ago