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2 years ago

10

Which expression is equal to StartAbsoluteValue negative 12 EndAbsoluteValue minus StartAbsoluteValue Negative 3 EndAbsoluteValu

e? –15 –9 9 15

2 answers:

Sedbober [7]2 years ago

3 0

Answer:

9.

Step-by-step explanation:

When there is an absolute value, anything within the absolute value becomes positive. Things outside the absolute values stay as they are.

|-12| - |-3| = 12 - 3 = 9.

Hope this helps!

JulijaS [17]2 years ago

3 0

Answer:

D

Step-by-step explanation:

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Lincoln Junior High School asked all of their eighth grade students the question, “What is your favorite breakfast?” and 18 perc

Rufina [12.5K]

Answer:

I hope this image and explanation helps you!

Step-by-step explanation:

All students in the eighth grade were surveyed, so we can make the valid conclusion that 18% of all students in the eighth grade at Lincoln Junior High School have pancakes as their favorite breakfast.

However, the question did not ask about the students' favorite meal of the day, so we cannot draw any valid conclusions about the students' favorite meal.

The valid conclusion:

18% of all students in the eighth grade at Lincoln Junior High School have pancakes as their favorite breakfast, but we cannot conclude anything about the percent of the population who have breakfast as their favorite meal.

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2 years ago

martin will roll a number of cube 150 times.The number cube is labeled 1 to 6.How many times could Martin expect to roll a numbe

olga_2 [115]

So the probability of rolling a number greater than 2 is 4/6. So 4/6 times 150 should give you the answer 100.

7 0

2 years ago

During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str

Brilliant_brown [7]

Answer:

number of successes

$k = 235$

number of failure

$y = 265$

The criteria are met

A

The sample proportion is $\r p = 0.47$

B

$E =4.4 \%$

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from the true population proportion will not more than 4.4%

Ci

$r = 0.514 = 51.4 \%$

$v = 0.426 = 42.6 \%$

D

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

E

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

Yes our result would support the claim because

$\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 500$

The sample proportion is $\r p = 0.47$

Generally the number of successes is mathematical represented as

$k = n * \r p$

substituting values

$k = 500 * 0.47$

$k = 235$

Generally the number of failure is mathematical represented as

$y = n * (1 -\r p )$

substituting values

$y = 500 * (1 - 0.47 )$

$y = 265$

for approximate normality for a confidence interval criteria to be satisfied

$np > 5 \ and \ n(1- p ) \ >5$

Given that the above is true for this survey then we can say that the criteria are met

Given that the confidence level is 95% then the level of confidence is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }$

substituting values

$E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }$

$E = 0.044$

=> $E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

substituting values

$0.47 - 0.044 < p < 0.47 + 0.044$

$0.426 < p < 0.514$

The upper limit of the 95% confidence interval is $r = 0.514 = 51.4 \%$

The lower limit of the 95% confidence interval is $v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } < \frac{1}{2} (50\%)$

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2 years ago

Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying

svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)' [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S) [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

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2 years ago

a bookshelf is 14 inches wide.there is enough space to fit 2 trophies one trophy is 2 inches wider than the other. how wide is t

Orlov [11]

The answer is 9 because half of 14 is 7, and 7+2=9

5 0

1 year ago

Read 2 more answers