Answer:
mean=4.44
standard deviation=1.67
Step-by-step explanation:
The mean and standard deviation for the number of erroneous returns per batch can be calculated using binomial distribution. The binomial distribution is used because
i) There are one of two possible outcomes( error or no error) that can be categorized into success and failure.
ii) The experiment is repeated fix number of times 12.
iii) The probability of success remains constant at each trial i.e. 37%
iv) The trails are independent.The mean and standard deviation of binomial distribution are np and √npq
Here, n=12, p=0.37 and q=1-0.37=0.63
mean=12*0.37=4.44
standard deviation=√12*0.37*0.63=√2.8=1.67
General Idea:
When a point or figure on a coordinate plane is moved by sliding it to the right or left or up or down, the movement is called a translation.
Say a point P(x, y) moves up or down ' k ' units, then we can represent that transformation by adding or subtracting respectively 'k' unit to the y-coordinate of the point P.
In the same way if P(x, y) moves right or left ' h ' units, then we can represent that transformation by adding or subtracting respectively 'h' units to the x-coordinate.
P(x, y) becomes 
. We need to use ' + ' sign for 'up' or 'right' translation and use ' - ' sign for ' down' or 'left' translation.
Applying the concept:
The point A of Pre-image is (0, 0). And the point A' of image after translation is (5, 2). We can notice that all the points from the pre-image moves 'UP' 2 units and 'RIGHT' 5 units.
Conclusion:
The transformation that maps ABCD onto its image is translation given by (x + 5, y + 2),
In other words, we can say ABCD is translated 5 units RIGHT and 2 units UP to get to A'B'C'D'.
He needs to score between 3.5 points more at the next game to make it to the all tournament team at the minimum. good luck with the question!!
Answer:
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
Step-by-step explanation:
<u>Equivalent algebraic expressions </u> are those expressions which on simplification give the same resulting<u> expression.</u>
Two algebraic <u>expressions</u> are said to be equivalent if their values obtained by substituting any values of the variables are same.
Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,
3f+2.6=3.1+2.6=3+2.6=5.6
2f +2.6=2.1+2.6=2+2.6=4.6
5.6≠ 4.6
Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.
3f+2.6=2f+2.6
3f=2f
3f-2f=0
f=0
This is true only when f=0.
Hence,
The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.
this what i know
