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2 years ago

6

martin will roll a number of cube 150 times.The number cube is labeled 1 to 6.How many times could Martin expect to roll a numbe

r greater than 2?

1 answer:

olga_2 [115]2 years ago

7 0

So the probability of rolling a number greater than 2 is 4/6. So 4/6 times 150 should give you the answer 100.

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The sample variance of hourly wages was 10. what is the sample standard deviation?

lapo4ka [179]

<span>Standard deviation is defined as the quantity which expresses by how much the members of a group is different from the mean value for the group.
</span>
The sample standard deviation with a <span>sample variance of hourly wages 10 will be $3.16.

Explanation:

</span><span>The standard deviation is the square root of the variance.
Therefore,
The square root of 10 dollars can be calculated as:

</span>√10 = $3.16

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2 years ago

Which expression is equivalent to (x^6y^8)^3\x^2y^2

Damm [24]

Answer:

$\large\boxed{\dfrac{(x^6y^8)^3}{x^2y^2}=x^{16}y^{22}}$

Step-by-step explanation:

$\dfrac{(x^6y^8)^3}{x^2y^2}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{(x^6)^3(y^8)^3}{x^2y^2}=\dfrac{x^{(6)(3)}y^{(8)(3)}}{x^2y^2}=\dfrac{x^{18}y^{24}}{x^2y^2}\qquad\text{use}\ \dfrac{a^m}{a^n}=a^{m-n}\\\\=x^{18-2}y^{24-2}=x^{16}y^{22}$

5 0

2 years ago

Read 2 more answers

Find the values for k so that the intersection of x = 2k and 3x + 2y = 12 lies in the first quadrant.

RUDIKE [14]

Answer:

0 < k < 2

Step-by-step explanation:

<u>In the first quadrant both of x and y get positive values, so </u>

x > 0 and y > 0

x = 2k, k > 0

<u>And replacing x with 2k in the second equation:</u>

3x + 2y = 12
3*2k + 2y = 12
2y= 12 - 6k
y = 6 - 3k

<u>Since y > 0:</u>

6 - 3k> 0
2 - k > 0
k < 2

<u>Combining both k > 0 and k < 2, we get:</u>

0 < k < 2

3 0

2 years ago

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A gardener uses a tray of 6 conical pots to plant seeds. Each conical pot has a radius of 3 centimeters and a depth of 8 centime

olga_2 [115]

I think 452cm^3
Voulme of one cylinder times 6

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2 years ago

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Two movie tickets and 3 snacks are $24. Three movies tickets and 4 snacks are $35. How much is a movie ticket and how much is a

Vsevolod [243]

Answer: A movie ticket is $9 while a snack is $2

Step-by-step explanation: We shall let a movie ticket be m while a snack is s. So, from the clues given, if two movie tickets and three snacks cost $24, we can write it as the following expression;

2m + 3s = 24

Also if three movie tickets and four snacks cost $35, we can as well write another expression as follows;

3m + 4s = 35.

Now we have a pair of simultaneous equations which are

2m + 3s = 24 ----------(1)

3m + 4s = 35 ----------(2)

We shall solve this by using the elimination method, since none of the variables has a coefficient of 1. We'll start by multiplying equation (1) by 3 and multiplying equation (2) by 2 (so as to eliminate the m variable)

2m + 3s = 24 -------- x3

3m + 4s = 35 ---------x2

We now arrive at the following

6m + 9s = 72--------(3)

6m + 8s = 70--------(4)

Subtract equation (4) from equation (3) and we arrive at

s = 2

Having determined that s equals 2 we can now substitute for the value of a into equation (1)

2m + 3s = 24

2m + 3(2) = 24

2m + 6 = 24

Subtract 6 from both sides of the equation

2m + 6 - 6 = 24 - 6

2m = 18

Divide both sides of the equation by 2

m= 9

Therefore one movie ticket costs $9 while one snack costs $2

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2 years ago