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jek_recluse [69]
2 years ago
13

A California distributor of sporting equipment expects to sell 10,000 cases of tennis balls during the coming year at a steady r

ate. Yearly carrying costs (to be computed on the average number of cases in stock during the year) are $10 per case, and the cost of placing an order with the manufacturer is $45. Determine the economic order quantity, that is, the order quantity that minimizes the inventory cost.
Mathematics
1 answer:
sleet_krkn [62]2 years ago
8 0

Economic Order Quantity

The economic order quantity, that is, the order quantity that minimizes the inventory cost is:

300 cases of tennis balls

Data and Calculations:

Sales of tennis balls for the coming year = 10,000 units

Carrying (holding) costs per case = $10

Cost of placing orders with the manufacturer = $45 per order

Economic Order Quantity (EOQ) = square root of (2 * Annual Demand/Sales * Ordering cost)/Carrying cost per case

= square root of (2 * 10,000 * $45)/$10

= square root of 90,000

= 300 tennis balls

This implies that the distributor will place about 33 orders in the coming year.  With each order, the quantity placed is 300 units.  This is the economic order quantity that will minimize its inventory cost for the year.

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A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip. On the return route, the boat trav
Georgia [21]

<em><u>The intervals included in solution are:</u></em>

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

<em><u>Solution:</u></em>

Given that,

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip

On the return route, the boat travels against the current, decreasing the boat's rate by 10 mph

The group needs to travel an average of at least 24 mph

<em><u>Given inequality is:</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}

<em><u>We have to solve the inequality</u></em>

\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}\\\\\frac{2}{x}  - 10\geq \frac{2}{24}

\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0

\frac{2}{x}-\frac{10}{1}-\frac{2}{24} \geq 0\\\\\frac{ 2 \times 24}{x \times 24} -\frac{10 \times 24}{1 \times 24} - \frac{2 \times x }{24 \times x}\geq 0\\\\\frac{48}{24x}-\frac{240x}{24x}-\frac{2x}{24x}\geq 0\\\\Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions\\\\\frac{48-240x-2x}{24x}\geq 0\\\\Add\:similar\:elements\\\\\frac{48-242x}{24x}\ge \:0

\mathrm{Multiply\:both\:sides\:by\:}24\\\\\frac{24\left(48-242x\right)}{24x}\ge \:0\cdot \:24\\\\Simplify\\\\\frac{48-242x}{x}\ge \:0\\\\Factor\ common\ terms\\\\\frac{-2\left(121x-24\right)}{x}\ge \:0\\\\\mathrm{Multiply\:both\:sides\:by\:}-1\mathrm{\:\left(reverse\:the\:inequality\right)}

When we multiply or divide both sides by negative number, then we must flip the inequality sign

\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0

\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\

This is attached as figure below

From the attached table,

\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0

<em><u>Therefore, solution set is given as</u></em>:

\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0

8 0
2 years ago
Read 2 more answers
Paul owns a gym and needs to replace the carpeting on the floor. The gym's floor plan is shown.
zubka84 [21]

Answer:

<em>24 square yards</em>

Step-by-step explanation:

Find the diagram attached.

The area of the diagram = Area of rectangle + Area of triangle

Area of rectangle = 3 * 4

Area of rectangle = 12 square yards

Area of triangle = 1/2 * base * height

Area of triangle = 1/2 * 6 * 4

Area of triangle = 12 square yards

Area of the diagram = 12 + 12

Area of diagram =  24 square yards

<em>Hence 24 square yards of carpeting is needed</em>

7 0
2 years ago
4C. Quintin is using the three different shaped
Sauron [17]

The smallest number of tiles Quintin will need in order to tile  his floor is 20

The given parameters;

  • number of different shapes of tiles available = 3
  • number of each shape = 5
  • area of each square shape tiles, A = 2000 cm²
  • length of the floor, L = 10 m = 1000 cm
  • width of the floor, W = 6 m = 600 cm

To find:

  • the smallest number of tiles Quintin will need in order to tile his floor

Among the three different shapes available, total area of one is calculated as;

A_{one \ square \ type} = 5 \times 2000 \ cm^2 = 10,000 \ cm^2

Area of the floor is calculated as;

A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2

The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

When all the three different shape types are used we can get the smallest number of tiles needed.

The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

3 0
2 years ago
Select all the points that are on the line through (0,5) and (2,8)
OverLord2011 [107]

Answer:

HI B , E

Step-by-step explanation:

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5 0
1 year ago
Sal was tired of waiting for Amir to show up at their meeting place, so he started running at an average speed of 4.5 mph withou
skelet666 [1.2K]
Let s and a represent the position of Sal and Amir respectively.

s=.75+4.5t  and a=-.25+6.7t

When Sal catches Amir, s=a so we can say.

-.25+6.7t=.75+4.5t  subtract 4.5t from both sides

-.25+2.2t=.75  add .25 to both sides

2.2t=1  divide both sides by 2.2

t=5/11 hours

t≈0.45 hours  (to nearest hundredth of an hour)
3 0
2 years ago
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