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2 years ago

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Ramesh examined the pattern in the table. Powers of 7 Value 2,401 343 49 7 1 Ramesh says that based on the pattern . Which state

ment explains whether Ramesh is correct?

2 answers:

earnstyle [38]2 years ago

7 0

1) You included neihter what Ramesh says nor the statements, then I can you tell some facts about the pattern.

2) The sequence is: 2401, 343, 49, 7, and 1.

3) The first term is 2401

4) The sequence is a decreasing geometric one.

5) The ratio is found dividing two consecutive terms (the second by the first, or the third by the second, or the fourth by the third, or the fifth by fourth):

1/7 = 7 / 49 = 49 / 343 = 343 / 2401.

So, the ratio is 1/7

6) The sum of that sequence is 2401 + 343 + 49 + 7 + 1 = 2801

Setler [38]2 years ago

6 0

Answer:

D. Ramesh is not correct because as the exponents decrease, the previous value is divided by 7

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) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.

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Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the 0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= $\dfrac{1}{2}$

The length of bits : n = 10

Let X = Number of getting ones.

Then , $X \sim Bin(n=10,\ p=\dfrac{1}{2})$

Binomial distribution formula : $P(X=x)=^nC_x p^x q^{n-x}$ , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , $p=q=\dfrac{1}{2}$

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

$P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}$

$=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}$

$=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})$

$=(\dfrac{1}{2})^{10}(210+252)$

$=(0.0009765625)(462)$

$=0.451171875\approx0.4512$

Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste

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1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)= $(x-a)^{3}$

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

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