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djverab [1.8K]
2 years ago
6

If the end behavior is increasing to the left, what might be true about the function? Select all that apply.

Mathematics
1 answer:
slava [35]2 years ago
6 0

The degree is even and the leading coefficient is positive

The degree is odd and the leading coefficient is negative

Step by step: Trust me

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A distribution for a set of wrist circumferences (measured in centimeters) taken from the right wrist of a random sample of newb
lozanna [386]

Answer:

A Histogram will be used to represent the size of right wrist of the random sample of newborn infants.

Step-by-step explanation:

A histogram is the graphical representation of the frequency distribution in the given sample. As the value of circumference can be a positive real number, therefore a Histogram with class boundaries can be formed such that the overall frequency of a wrist size is also visible in the graph.

Also as the distribution will be of continuous nature thus a histogram is a more suitable option as compared to a bar or stem and leaf graph.

3 0
2 years ago
Write 337,060 in expanded form using exponents
Lerok [7]
3 x 10 to the sixth power
3 x 10 to the fifth power
7 x 10 to the fourth power
6 x 10 to the first power

I might be wrong though. If so, sorry!
4 0
2 years ago
Read 2 more answers
Which are the solutions of x2 = 19x + 1?
Finger [1]

Answer:

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

Step-by-step explanation:

we have

x^2=19x+1

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2}-19x-1=0  

so

a=1\\b=-19\\c=-1

substitute in the formula

x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}

x=\frac{19\pm\sqrt{365}} {2}

x=\frac{19+\sqrt{365}} {2}

x=\frac{19-\sqrt{365}} {2}

(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0
2 years ago
Read 2 more answers
One way to solve the system is to _____________ a variable.
Ivahew [28]

One way to solve the system is to <u>substitute</u> a variable.

<u>Explanation:</u>

One approach to solve an equation is by substitution of one variable. Right now, a condition for one factor, at that point substitute that arrangement in the other condition, and explain. All value(s) of the variable(s) that fulfills a condition, disparity, arrangement of conditions, or arrangement of imbalances.

The technique for tackling "by substitution" works by settling one of the conditions (you pick which one) for one of the factors (you pick which one), and afterward stopping this go into the other condition, "subbing" for the picked variable and fathoming for the other. At that point you back-explain for the principal variable.

8 0
2 years ago
Read 2 more answers
Which of the following represents the zeros of f(x) = 5x3 − 6x2 − 59x + 12? (2 points)
Furkat [3]

Answer:

4, −3, 1 over 5

Step-by-step explanation:

x is a zero of f(x) if f(x) = 0

In this problem, we have that:

f(x) = 5x^{3} - 6x^{2} - 59x + 12

4, 3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, 3, − 1 over 5

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, −3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(\frac{1}{5}) = f(0.2) = 5*(0.2)^{3} - 6*(0.2)^{2} - 59*(0.2) + 12 = 0

So 1 over 5 is a zero of the function

This is the correct answer.

4, −3, −1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(-\frac{1}{5}) = f(-0.2) = 5*(-0.2)^{3} - 6*(-0.2)^{2} - 59*(-0.2) + 12 = 23.52

-1 over 5 is not a zero of the function

5 0
2 years ago
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