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zhannawk [14.2K]
2 years ago
9

You offer senior citizens a 20 percent discount on their meal prices served at your cafeteria. Assuming that an average of 150 s

enior citizens eat daily at your cafeteria and that the average price of their meals before discount is $5.95, how much total discount do you give on an average daily basis? A. 1,79 B. 17.85 C. 178.50 D. 1785.00
Mathematics
2 answers:
Katarina [22]2 years ago
6 0
20% • $5.95= $1.19 
150 • $1.19 = $178.50
Your answer is C.

scoray [572]2 years ago
3 0

Given, there are an average of 150 citizens eat daile in the cafeteria.

The average price of their meals = $5.95.

The discount given for sinior citizens in their meals = 20%

So we have to find 20% of $5.95 first.

20% of $5.95 = (5.95)(\frac{20}{100} )

= \frac{(5.95)(20)}{100}

= \frac{119}{100}

= 1.19

So, the amount of discount given to the senior citizens = $1.19 per head.

As there are 150 cinior citizens daily.

So total discount given daily = $(150)(1.19) =$178.5

So we have got the required answer.

Option C is correct here.

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Step-by-step explanation:

x² - 3x - 10 =

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The length of the missing piece is 2 ft 3 inches

Step-by-step explanation:

Here in this question, we are interested in calculating the length of the remaining piece of the board given that we have the total length of the board and two other pieces.

Mathematically, the remaining piece length can be calculated by subtracting the lengths of the known pieces

That would be;

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In a foot there are 12 inches

Thus

10 ft = 10 * 12 = 120 inches

4 ft 7 inches = 4(12) + 7 = 55 inches

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120 -55 -38 = 27 inches

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1 year ago
A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si
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Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

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x = \frac{128}{y}

When 1 inch margin is at top and bottom

The length becomes:

Length = x + 1 + 1

Length = x + 2

When 2 inch margin is at both sides

The width becomes:

Width = y + 2 + 2

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The New Area (A) is then calculated as:

A = (x + 2) * (y + 4)

Substitute \frac{128}{y} for x

A = (\frac{128}{y} + 2) * (y + 4)

Open Brackets

A = 128 + \frac{512}{y} + 2y + 8

Collect Like Terms

A = \frac{512}{y} + 2y + 8+128

A = \frac{512}{y} + 2y + 136

A= 512y^{-1} + 2y + 136

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

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Set

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0 = -512y^{-2} + 2

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512y^{-2} = 2

Multiply through by y^2

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Divide through by 2

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Take square roots of both sides

\sqrt{256=y^2

16=y

y = 16

Recall that:

x = \frac{128}{y}

x = \frac{128}{16}

x = 8

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Length = x + 2

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To double-check;

Differentiate A'

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The above value is:

A" = \frac{1024}{y^3} > 0

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

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Answer:

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6 0
2 years ago
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