The price of a ring was increased by 8% to £486. What was the price before the increase?

On some days,Melvin commutes 3.5 hours per day to the city for business meetings.Last week he commuted for a total of 14 hours.H

DanielleElmas [232]

Formula:

Total hours ÷ hour per day

14 ÷ 3.5 = 4.

The answer is 4.

He commuted 4 days for the city.

3 0

2 years ago

On a coordinate plane, a piecewise function has 3 lines. The graph shows cleaning time in hours on the x-axis and total cost in

sveta [45]

Answer:

C. (2, 6] hour jobs cost $100

Step-by-step explanation:

Let's consider each of these statements in view of the graph:

A cleaning time of 2 hours will cost $100. -- The closed circle at (2, 50) tells you the cost of a 2-hour job is $50, not $100.
A cleaning time of 6 hours will cost $150. -- The closed circle at (6, 100) tells you the cost of a 6-hour job is $100, not $150.
Cost is a fixed rate of $100 for jobs requiring more than 2 hours, up to a maximum of 6 hours. -- The line between the open circle at (2, 100) and the closed circle at (6, 100) tells you this is TRUE.
Cost is a fixed rate of $200 for jobs that require at least 6 hours. -- "At least 6 hours" means "greater than or equal to 6 hours." The closed circle at (6, 100) means a 6-hour job is $100, not $200.

3 0

2 years ago

The infield of a baseball field is a square

AnnZ [28]

Answer:

106.1 ft/s

Step-by-step explanation:

You know the diagonal of a square is √2 times the length of one side, so the distance from 3rd to 1st is 90√2 feet ≈ 127.2792 ft.

The speed is the ratio of distance to time:

speed = distance/time = 127.2972 ft/(1.2 s) ≈ 106.1 ft/s.

_____

In case you have never figured or seen the computation of the diagonal of a square (the hypotenuse of an isosceles right triangle), consider the square with side lengths 1. The diagonal will cut the square into halves that are isosceles right triangles with leg lengths 1. Then the Pythagorean theorem can be used to find the diagonal length d:

d² = 1² + 1²

d² = 2

d = √2

Since this is the diagonal for a side length of 1, any other side length will serve as a scale factor for this value. A square with a side length of 90 ft will have a diagonal measuring 90√2 ft.

7 0

2 years ago

Yesterday's World Cup final had viewing figures of 138,695,157.<br><br> What is the value of the 3?

crimeas [40]

Answer:

The value of the 3 is 30,000,000.

Step-by-step explanation:

From the digit at the right, you go multiplying each element by 10 powered to a counter that starts at zero and increases at every digit. So:

Our counter is i

i = 0;

v(7) is the value of the 7

$v(7) = 7*10^{0} = 7$

i = 1;

v(5) is the value of the 5

$v(5) = 5*10^{1} = 50$

i = 2;

v(1) is the value of the 1

$v(1) = 1*10^{2} = 100$

i = 3;

v(5) is the value of the 5

$v(5) = 5*10^{3} = 5,000$

i = 4;

v(9) is the value of the 9

$v(9) = 9*10^{4} = 90,000$

i = 5;

v(6) is the value of the 6

$v(6) = 6*10^{5} = 600,000$

i = 6;

v(8) is the value of the 8

$v(8) = 8*10^{6} = 8,000,000$

i = 7;

v(3) is the value of the 3

$v(3) = 3*10^{7} = 30,000,000$

The value of the 3 is 30,000,000.

8 0

2 years ago

A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1863 mailboxes t

worty [1.4K]

Answer:

3433 m²

Step-by-step explanation:

From the image, we have a rectangular box without cover and half a cylinder on top.

Formula for surface area of rectangular box with top is;

S = 2(lh + wh + lw)

From the image,

l = 0.6 m

w = 0.4 m

h = 0.55 m

Thus;

S = 2((0.6 × 0.55) + (0.4 × 0.55) + (0.6 × 0.4))

S = 1.58 m²

Now, since the top is not included for this figure, then;

Surface area of this rectangular box is;

S1 = 1.58 - (lw) = 1.58 - (0.4 × 0.6) = 1.34 m²

Surface area of a cylinder is;

S = 2πr² + 2πrh

r is radius and in this case = 0.4/2 = 0.2 m

h = 0.6

S = 2π(0.2² + (0.2 × 0.6))

S = 1.005 m²

Since it is half cylinder, then we have;

S2 = 1.005/2

S2 = 0.5025 m²

Total surface area; S_t = S1 + S2

S_t = 1.34 + 0.5025

S_t = 1.8425 m²

This is the surface area of one mail box.

Thus, for 1863 mailboxes, total surface area is;

S = 1863 × 1.8425 = 3432.5775 m²

Approximating to the nearest Sq.m gives;

S = 3433 m²

6 0

2 years ago