Answer:
Step-by-step explanation:
a)
Test statistic:
here test statistic lie in rejection region,that why null hypothesis fails
so Yes, its significant.
b)
Test statistic:
c)
sample variability increases, therefore likelihood of rejecting the null hypothesis decreases.
3000000...........
10^6 =1000000 (3) = 3000000
Answer:
The mean is the better method.
Step-by-step explanation:
The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.
The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.
As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.
You'll need to give a bit more information for the question to be answered. You can only calculate the percentage of error if you know what the mass of the substance *should be* and what you've *measured* it to be.
In other words, if a substance has a mass of 0.55 grams and you measure it to be 0.80 grams, then the percent of error would be:
percent of error = { | measured value - actual value | / actual value } x 100%
So, in this case:
percent of error = { | 0.80 - 0.55 | / 0.55 } x 100%
percent of error = { | 0.25 | / 0.55 } x 100%
percent of error = 0.4545 x 100%
percent of error = 45.45%
So, in order to calculate the percent of error, you'll need to know what these two measurements are. Once you know these, plug them into the formula above and you should be all set!
