The price of a ring was increased by 8% to £486. What was the price before the increase?

What is the standard deviation of the market portfolio if the standard deviation of a fully diversified portfolio with a beta of

Nina [5.8K]

Answer:

22.5%

Step-by-step explanation:

let the standard deviation for market portfolio = σₙ

Also let the standard deviation for fully diversified portfolio = σₓ

To calculate fully diversified portfolio

fully diversified portfolio has σₓ = βσₙ

From the given question beta (β) = 1.25

Also standard deviation for market portfolio (σₙ) = 18% = 0.18

From the equation above, σₓ = βσₙ = 1.25×0.18 = 0.225

= 22.5% (converting to percentage)

3 0

2 years ago

Bernie helped design a magician costume for a school play. He used 5.75 feet of ribbon for the magician's wand. He used 11.75 fe

Nonamiya [84]

Answer:

The ribbon cost per foot $0.6 per foot

Step-by-step explanation:

Total number of ribbon used = (5.75 + 11.75) = 17.50 feet

17.50 feet of ribbon cost = $10.50

1 foot of ribbon cost = x

Cross Multiply

17.50 × x = 1 foot × $10.50

x = 1 foot × 10.50/17.50

x = $0.6

The ribbon cost per foot $0.6 per foot

8 0

2 years ago

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The table represents a linear function. A two column table with six rows. The first column, x, has the entries, negative 2, nega

Radda [10]

Answer: The slope is 3

Step-by-step explanation:

For each unit of run in the x-values, there is an increase of 3 in the y-values. Slope is Rise over Run so 3/1 = 3

8 0

2 years ago

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is $\overline A=\textrm{Missing a target at least once}$

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, $P(A)=0.95^{10}=0.5987$

We know that the sum of probability of an event and its complement is 1.

So, $P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%$

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0

2 years ago

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In measuring reaction time, a psychologist estimates that a standard deviation is .05 seconds. How large a sample of measurement

blondinia [14]

Answer:

97

Step-by-step explanation:

We are asked to find the size of sample to be 95% confident that the error in psychologist estimate of mean reaction time will not exceed 0.01 seconds.

We will use following formula to solve our given problem.

$n\geq (\frac{z_{\alpha/2}\cdot\sigma}{E})^2$ , where,

$\sigma=\text{Standard deviation}=0.05$ ,

$\alpha=\text{Significance level}=1-0.95=0.05$ ,

$z_{\alpha/2}=\text{Critical value}=z_{0.025}=1.96$ .

$E=\text{Margin of error}$

$n=\text{Sample size}$

Substitute given values:

$n\geq (\frac{z_{0.025}\cdot\sigma}{E})^2$

$n\geq (\frac{1.96\cdot0.05}{0.01})^2$

$n\geq (\frac{0.098}{0.01})^2$

$n\geq (9.8)^2$

$n\geq 96.04$

Therefore, the sample size must be 97 in order to be 95% confident that the error in his estimate of mean reaction time will not exceed 0.01 seconds.

5 0

2 years ago