Answer:
Largest possible length is <em>21 inches</em>.
Step-by-step explanation:
Given:
Total material available = 60 inches
Length to be 3 more than twice of width.
To find:
Largest possible length = ?
Solution:
As it is rectangular shaped frame.
Let length =
inches and
Width =
inches
As per given condition:
..... (1)
Total frame available = 60 inches.
i.e. it will be the perimeter of the rectangle.
Formula for perimeter of rectangle is given as:

Putting the given values and conditions as per equation (1):

Putting in equation (1):

So, the answer is:
Largest possible length is <em>21 inches</em>.
Answer: (-4,-8)
Step-by-step explanation: I got a 100% on the quiz
The average price of such a house is
(97.86/ft²)×(1400 ft²) = 97.86×1400 = 137,004
First of all, lets consider that you made a litte mistake and you meant this problem.........
<span>"The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than the average weight of one okapi. On average, how much does an okapi weigh, and how much does a llama weigh?"
This is a system of two equations.
Let it be X the average weight of a LLAMA
And Y the average weight of an OKAPI
X + Y = 450 kg 1)
3X = 190 kg +Y 2)
So, with 1) we have that Y = 450 - X
We subsitute in 2) and we have
3X = 190 + (450 -X).............We solve for X ....==> 4X = 640kg ==> X = 160kg
..We replace X in 1 and get => Y = 450kg -X = 450kg -160kg = 290kg
</span>160kg....... average weight of a LLAMA
290kg........average weight of an OKAPI