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1 year ago

What value of x is in the solution set of 2(3x - 1) = 4x - 6? EO -10

Mathematics

2 answers:

lakkis [162]1 year ago

8 0

Answer:

x = - 1

Step-by-step explanation:

Given

2(3x - 1) ≥ 4x - 6 ← distribute parenthesis on left side

6x - 2 ≥ 4x - 6 ( subtract 4x from both sides )

2x - 2 ≥ - 6 ( add 2 to both sides )

2x ≥ - 4 ( divide both sides by 2 )

x ≥ - 2

The only value in the list greater than - 2 is - 1

x = - 1 is in the solution set

tensa zangetsu [6.8K]1 year ago

5 0

Answer:

D) -1

Step-by-step explanation:

6x-2≥4x-6

6x-4x≥-6+2

2x≥-4

x≥-4÷2

x≥-2

Only -1 is greater than -2 in the list.

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Answer:

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The simplified base is 8.

Step-by-step explanation:

The given function is $f(x) = 3(16)^{\frac{3}{4}x }$ ......... (1)

Therefore, the initial value of the function at x = 0 is $f(0) = 3(16)^{0} = 3$

Now, the domain can be any real value, since for all real value of x, y exists.

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