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Volgvan
1 year ago
13

If a person invests $220 at 7% annual interest, find the approximate value of the investment at the end of 10 years.

Mathematics
2 answers:
xz_007 [3.2K]1 year ago
6 0
The amount is $432.77 and the interest is $212.77

frez [133]1 year ago
5 0

\bf ~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$220\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years\dotfill &10 \end{cases} \\\\\\ A=220[1+(0.07)(10)]\implies A=220(1.7)\implies A=374

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The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?
Aleks04 [339]

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

  • The selling price of a box of crackers is $1.75
  • You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = \frac{New-Old}{old} × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = \frac{2.54-1.75}{1.75} × 100%

∴ The markup percentage = \frac{0.79}{1.75} × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

#LearnwithBrainly

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2 years ago
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The SAT mathematics scores in the state of Florida are approximately normally distributed with a mean of 500 and a standard devi
ivann1987 [24]
Since the range of the scores given was between 300 and 700 (which is 2 standard deviations below and above the mean), the probability that a randomly selected student's math score - as based on the empirical rule of statistics - is 95%. In decimal form, it is .95. 
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1 year ago
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Given: AD = BC and AD || BC<br><br><br> Prove: ABCD is a parallelogram.
maksim [4K]

Answer:

ABCD is a parallelogram

Step-by-step explanation:

Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a

parallelogram. Statements Reasons 1. AD ≅ BC; AD ∥ BC

1. given 2. ∠CAD and ∠ACB are alternate interior ∠s 2.

definition of alternate interior angles 3. ∠CAD ≅ ∠ACB 3.

alternate interior angles are congruent 4. AC ≅ AC 4.

reflexive property 5. △CAD ≅ △ACB 5. SAS congruency

theorem 6. AB ≅ CD 6. ? 7. ABCD is a parallelogram 7.

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1 year ago
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Enzo is studying the black bear population at a large national park.
Naddik [55]

Answer:

2,973

Step-by-step explanation:

The black bear population B(t), in the park is modeled by the following function:

B(t) = 2500 \cdot 2^{0.01t}

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973

There will be 2,973 black bears in 25 years time.

4 0
1 year ago
Which expression has the same GCF as 15x2 - 21x?
Mice21 [21]

Answer:

15x^2 +21 x

Step-by-step explanation:

We have the following expression:

15x^2 -21 x

We can find the GCF with the following steps.

1. Find the GCF for the numerical part 15 and -21

The factors for 15 are : 1,3,5,15

The factors for -21 are -21,-7,-3,-1,1,3,7,21

And the common factors are 1,3

The GCF for the numerical part is 3*1 = 3

2. Find the GCF for the variable

The factors of x^2 are : x*x

The factors of x are: x

The common factors are x for this case, so then the GCF for the variable part is x

3. Multiply the two results from steps 1 and 2

GCf= 3*x = 3x

If we consider the new expression:

15x^2 +21x

We can find the GCF with the following steps.

1. Find the GCF for the numerical part 15 and -21

The factors for 15 are : 1,3,5,15

The factors for -21 are 1,3,7,21

And the common factors are 1,3

The GCF for the numerical part is 3*1 = 3

2. Find the GCF for the variable

The factors of x^2 are : x*x

The factors of x are: x

The common factors are x for this case, so then the GCF for the variable part is x

3. Multiply the two results from steps 1 and 2

GCf= 3*x = 3x

And as we can see both GCF are equal. So then we satisfy the condition required.

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1 year ago
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