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1 year ago

What angle does an arc 6.6cm in length subtends at the centre of a circle of radius 14cm. Use π = 22/7)

Mathematics

2 answers:

vivado [14]1 year ago

6 0

Answer:

27°

Step-by-step explanation:

arc length = circumference × fraction of circle

let x be the central angle, then

2πr × $\frac{x}{360}$ = 6.6

2 × $\frac{22}{7}$ × 14 × $\frac{x}{360}$ = 6.6

88 × $\frac{x}{360}$ = 6.6 ( multiply both sides by 360 )

88x = 2376 ( divide both sides by 88 )

x = 27

Thus central angle is 27°

aniked [119]1 year ago

4 0

Answer:

STEP 1: Find the circumference:

Circumference = 2πr

Circumference = 2π(14) = 28π cm

............................................................................................

STEP 2: Find the length of the arc:

Length of the arc = 36/360 x 28π

Length of the arc = 8.8 cm

.............................................................................................

Answer: The length of the arc is 8.8 cm

............................................................................................

hope it helpssss

Mark it as brilliant answer plzzz

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Claire invests £200 000 in a savings account for 4 years.

Nutka1998 [239]

Answer:

125,000 is the correct answer

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2 years ago

Read 2 more answers

The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi

Ivanshal [37]

Answer:

P(X \le 250 ) = 0.7564 [/tex] , $P(X < 250 ) = 0.7564$ ,

$P(X < 300 ) = 0.09922$

$P(100 < X < 250 ) =0.644$

$x = 192.1$

Step-by-step explanation:

From the question we are told that

The value for $\alpha = 2.6$

The value for $\beta = 220$

Generally the Weibull distribution function is mathematically represented as

$F( x , \alpha , \beta ) = \left \{ 0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x < 0} \atop { 1- e^{-(\frac{x}{\beta } )^{\alpha } }}\ \ \ \ \ \ x \ge 0} \right$

Generally the probability that a specimen's lifetime is at most 250 is mathematically represented as

$P(X \le 250 ) = F(250, 2.7 , 220 )$

$P(X \le 250 )=1 - e^{- (\frac{250}{220} )^{2.7}}$

$P(X \le 250 ) = 1 - 0.2436$

$P(X \le 250 ) = 0.7564$

Generally the probability that a specimen's lifetime is less than 250

$P(X < 250 ) = F(250, 2.7 , 220 )$

[texP(X < 250 ) =1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]

$P(X < 250 ) = 1 - 0.2436$

$P(X < 250 ) = 0.7564$

Generally the probability that a specimen's lifetime is more than 300

$P(X > 300 ) = 1- p(X \le 300 )$

$P(X > 300 ) = 1- F(300, 2.7 , 220 )$

[texP(X < 300) =1- [1 - e^{- (\frac{300}{220} )^{2.7}}][/tex]

$P(X < 300 ) = 0.09922$

Generally the probability that a specimen's lifetime is between 100 and 250 is

$P(100 < X < 250 ) = P(X < 250) - P(X < 100)$

=> $P(100 < X < 250 ) =F(250 , 2.7 , 220 ) - F(100 , 2.7 , 220 )$

=> $P(100 < X < 250 ) =(1 - e^{-(\frac{250}{220})^{2.7}}) - (1 - e^{-(\frac{100}{220})^{2.7}})$

=> $P(100 < X < 250 ) = (1 - 0.244 ) - (1- 0.888)$

=> $P(100 < X < 250 ) =0.644$

Generally the value such that exactly 50% of all specimens

$P(X > x) = 1-P(X < x) = 0.50$

=> $P(X > x) = 1- (1 - e^{- (\frac{x}{220}) ^{2.7}}) = 0.50$

=> $P(X> x ) = e^(- \frac{x}{20})^{2.7} = 0.50$

=> $P(X> x ) = (- \frac{x}{20})^{2.7} = ln0.50$

=> $P(X> x ) = \frac{x}{20} =[ -ln0.50 ] ^{frac{1}{2.7}}$

=> $x = 220[ -ln0.50 ] ^{frac{1}{2.7}}$

=> $x = 192.1$

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1 year ago

What number has 2 more tens than 40 and the same number of ones as 18

Juli2301 [7.4K]

The answer is 68.
To solve 2 more tens than 40, you add 20 to 40, which is 60.
To solve for the same number of ones as 18, then it would only be 68.

Hope this helps!!

5 0

1 year ago

A grocery store sells packages of beef. The function C(w) represents the cost, in dollars, of a package of beef weighing w pound

victus00 [196]

Answer:

(4)

Step-by-step explanation:

Integers are: ... -3, -2, -1, 0, 1, 2, 3 ....

Positive integers are the positive ones of the line above.

Rational numbers include all the numbers between the whole ones, so fractions and decimals included. Any number that can be written as a fraction (including repeating decimals).

Now, domain is the set of x-values (input) of the function.

The input of the function C(w), is w, which is the number of pounds.

You can buy 3 pounds, 4 pounds etc. as well as 3.2 pounds, 3/4 pound etc.

So, you can buy rational numbers number of pounds, not only integers.

Also, NOT ALL RATIONALS, since you can't buy NEGATIVE POUNDS of beef, so we can say:

THe domain is positive rational numbers.

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2 years ago

If m∠ABC = 45° and m∠ECD = 45°, which statement explains whether the AA similarity postulate can be used to determine whether ΔB

LekaFEV [45]

Answer:

No, the AA similarity postulate cannot be used because a reflection over line f will establish that ∠ABC and ∠DEC are not congruent.

Step-by-step explanation:

Data provided in the question

m∠ABC = 45°

m∠ECD = 45°

Based on the above information, the ΔBAC ~ ΔEDC could be determined by seeing the given options

As we can see that from the last option the AA could not be postulated as it creates a reflection over the line plus the ∠ABC and ∠DEC is not congruent

Therefore the last option is correct

7 0

1 year ago