The probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48 and of owning both is 0.45.
1 answer:
Answer:
The probability that the middle school student owns a skateboard or a bicycle is 0.61.
Step-by-step explanation:
We are given that the probability of a middle school student owning a skateboard is 0.58, of owning a bicycle is 0.48, and owning both is 0.45.
A middle school student is chosen at random.
Let the probability of student owning a skateboard = P(S) = 0.58
The probability of student owning a bicycle = P(B) = 0.48
The probability of student owning both = P(S B) = 0.45
Now, the probability that the middle school student owns a skateboard or a bicycle is given by = P(S B)
P(S B) = P(S) + P(B) - P(S
B)
= 0.58 + 0.48 - 0.45
= 0.61
Hence, the probability that the middle school student owns a skateboard or a bicycle is 0.61.
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Answer:
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
Step-by-step explanation:
z-score:
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
January:
The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that . So
February:
The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that . So
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.