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Elis [28]
2 years ago
7

The median of $20, x, 15, 30, 25$ is $0.4$ less than the mean. If $x$ is a whole number, what is the sum of all possible values

of $x$?
Mathematics
1 answer:
34kurt2 years ago
5 0

Answer:

198

Step-by-step explanation:

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A machine can stamp 75 caps per minute. At this rate how long will it take to stamp 3000?
Leya [2.2K]
<h2>Answer:</h2><h2>40 minutes</h2>

Step-by-step explanation:

75- caps ----------- 1 minute\\3000 caps ------------x - minutes\\\\Cross-Multiply\\75x = 3000 \times 1\\75x = 3000\\\frac{75}{75} =\frac{3000}{75} \\\\x = 40 minutes

6 0
2 years ago
Read 2 more answers
Find the x if the sequence 3, x, 4x/3 is (a)arithmetic and (b)geometric
jolli1 [7]

(a) When the sequence is arithmetic, sequential terms have a common difference.

... x - 3 = (4x/3) - x . . . . differences of sequential terms are equal

... (2/3)x = 3 . . . . . . . add 3-(1/3)x

... x = 9/2 . . . . . . . . . multiply by 3/2

(The arithmetic sequence is 3, 4.5, 6. The common difference is 3/2.)

(b) When the sequence is geometric, sequential terms have a common ratio.

... x/3 = (4x/3)/x . . . . . ratios of sequential terms are equal

... x^2 = 4x . . . . . multiply by 3x

... x = 4 . . . . . . . . divide by x. (the "solution" x=0 is extraneous)

(The geometric sequence is 3, 4, 16/3. The common ratio is 4/3.)


6 0
2 years ago
Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
2 years ago
How much profit was generated by the sales of gold label and black label combined?
blsea [12.9K]

The<u> profit</u> genereted  by the <u>sales of gold label and black label combined</u> is <u>the sum</u> of the profits generated by the sales of gold label and of the profits generated by the sales of black label.

1. From the table

\begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Gold label}&1,000&\$2.75\end{array}

you can find the profits generated by the sales of gold label:

1,000\cdot \$2.75=\$2,750.

2. From the table

\begin{array}{ccc}&\text{Number of bottles sold}&\text{Average profit (per bottle)}\\\text{Black label}&2,000&\$1.50\end{array}

you can find the profits generated by the sales of black label:

2,000\cdot \$1.50=\$3,000.

In total

\$2,750+\$3,000=\$5,750.

Answer: correct option 5

8 0
2 years ago
Read 2 more answers
Suppose Frances is a researcher at Beaded Gemsz, a company that makes beaded jewelry. She wants to evaluate whether using better
Natalija [7]

Answer:

There is 8% (P=0.08) that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect.

Step-by-step explanation:

We have one-sample z-test with a significance level of 0.08 and a power ot the test of 0.85.

In this test, the null hypothesis will state that the new equipment has the same  productivity of the older equipment. The alternative hypothesis is that there is a significative improvement from the use of new equipment.

The probability that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect is equal to the probability of making a Type I error (rejecting a true null hypothesis).

The probability of making a Type I error is defined by the level of significance, and in this test this value is α=0.08.

Then, there is 8% that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect.

6 0
2 years ago
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