A new car is purchased for 23900 dollars. The value of the car depreciates at 14.25% per year. To the nearest tenth of a year, h
2 answers:
Answer:
The value of the car will be 6100 dollars in 8.8 years
Step-by-step explanation:
Present value of car = $23900
The value of the car depreciates at 14.25% per year
Let x be no. of years in which the value of the car becomes 6100 dollars
Formula:
Substitute the values :
Hence the value of the car will be 6100 dollars in 8.8 years
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Answer:
C. Those who have a car tend to have a cell phone.
Step-by-step explanation:
The relative frequency for a data set n is calculated by dividing each frequency by n.
We have a table that relates the use of cars and cell phones.
First, we take from the table the population that has a car.
Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.
Then we calculate the relative frequencies for those who have a cell phone and those who do not.
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Relative frequency Students with car n = 18.
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C<em>ell phone No cell phone Total n</em>
12/18 6/18 18
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_______________________________________________
Relative frequency Students with car n = 18.
-------------------------------------------------- --------------------------------------
C<em>ell phone No cell phone Total n</em>
0.666 0.333 18
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Most students who have a car also have a cell phone.
Now we calculate the relative frequency for students who do not have a car.
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Relative frequency Students without a car n = 7
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<em>Cell phone No cell phone Total n</em>
2/7 5/7 7
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_______________________________________________
Relative frequency Students without a car n = 7
-------------------------------------------------- --------------------------------------
<em>Cell phone</em> <em> No</em> <em>cell phone Total n</em>
0.286 0.714 7
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Most students who do not have a car do not have a cell phone either.
<em>Then these data suggest that. Those who have a car tend to have a cell phone.</em>
Option C
Answer:
2, 2, 4, 6, 4
Step-by-step explanation:
Fundamental Theorem of Algebra states that 'An 'n' degree polynomial will have n number of real roots'.
1. The polynomial is given by
So, on simplifying we get that, .
Since, degree of polynomial is 5, it will have 5 roots.
This gives us that the roots of the equation are x = 0, -2, 2, 4i and -4i
So, the number of complex roots are 2.
2. The polynomial is given by
Since, degree of polynomial is 4, it will have 4 roots.
Equating them both by zero, and
gives that the roots of the polynomial are x = 2i, -2i, -5, -5.
So, the number of complex roots are 2.
3. The polynomial is given by
Since, degree of polynomial is 6, it will have 6 roots.
On simplifying, we get that the real roots of the polynomial are x = -1.75 and x = 4.28.
So, the number of complex roots are 6-2 = 4.
4. The polynomial is given by
Since, degree of polynomial is 7, it will have 7 roots.
On simplifying, we get that the only real root of the polynomial is x = -2.
So, the number of complex roots are 7-1 = 6.
5. The polynomial is given by
Since, degree of polynomial is 5, it will have 5 roots.
Simplifying the equation gives
Equating each to 0, we get the real roots of the polynomial is
So, the number of complex roots are 5-1 = 4