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Nitella [24]
2 years ago
12

Evan went to the park and saw for animals each animal was either a duck or dog if he saw a total of 14 legs how many of each ani

mal did he see
Mathematics
1 answer:
beks73 [17]2 years ago
7 0

Answer:

Two dogs and three ducks

Step-by-step explanation:

Dogs have four legs and ducks have two, to find the answer, you add the number to get your answer.

In this case, two dogs would make a total of 8 legs and three ducks would make a total of 6 legs. Adding 8 and 6 together, you get 14.


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An employee worked 36 hours last week. This week, she worked 48 hours. Find the percent increase. Round to the nearest percent.
ioda

Answer:

There was a 25% increase.

Step-by-step explanation:

6 0
1 year ago
The warehouse already has 27 pallets of stock waiting to be unloaded, and the delivery van arrives with another 8. The warehouse
Natasha_Volkova [10]
To find the answer you would add 27 and 8 together which would give you 35. Once you've done that, you would subtract 32 from 35 which would give you 3 meaning that there will be 3 pallets left over as your answer.
5 0
2 years ago
is the sum of two polynomials of degree 5 always a polynomial of degree 5? Give an example to explain your answer
ddd [48]
A counter example is

f(x)=5x^5+2x^3+3x
g(x)=-5x^5-x^4+x^2-4

Then f(x)+g(x) = -x^4+2x^3+x^2+3x-4  which is a polynomial of degree 4.

So the answer is no.  Counter-example is given above.
7 0
2 years ago
Liner equation Melissa and Jane are planting trees Melissa plants 10 tree in 1 hour Jane plants 17 trees in 2 hours enter an equ
levacccp [35]

Answer:

6 hours

Step-by-step explanation:

What we must do is calculate the speed of each one,

Melissa in one hour plants 10 trees, that is 10/1 is her speed.

Jane in two hours plants 17 trees, that is 17/2 is her speed.

Now, we want to know the time it takes to plant 11 trees, so the sum of the previous speeds is equal to 111 / x

10/1 + 17/2 = 111 / x

18.5 = 111 / x

x = 111 / 18.5

x = 6

Which means that in 6 hours between the two they can plant 111 trees

8 0
1 year ago
A tank initially contains 40 ounces of salt mixed in 100 gallons of water. a solution containing 4 oz of salt per gallon is then
stellarik [79]
Let A(t) be the amount of salt in the tank at time t. We're given that A(0)=40. The rate at which this amount changes is given by

A'(t)=\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{4\text{ oz}}{1\text{ gal}}-\dfrac{5\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ oz}}{100+(5-5)t\text{ gal}}

A'(t)+\dfrac{A(t)}{20}=20

e^{t/20}A'(t)+e^{t/20}\dfrac{A(t)}{20}=20e^{t/20}

\bigg(e^{t/20}A(t)\bigg)'=20e^{t/20}

e^{t/20}A(t)=400e^{t/20}+C

A(t)=400+Ce^{-t/20}

Since A(0)=40, we get

40=400+C\implies C=-360

so that the amount of salt at time t is

A(t)=400-360e^{-t/20}

After 20 minutes, the tank contains

A(20)=400-360e^{-20/20}\approx267.56\text{ oz}
6 0
2 years ago
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