Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe, 
= 120 cm
Its wavelength 
= 480 cm
= 160 cm and 
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
So the pipe is open at one end and closed at one end
.
9.2 x 13.8 = 126.96, now usually to get the area of a triangle we would half this but because we have two of the same triangle we would then have to double it again so they cancel each other out. We then do 6.9 x 9.2 which equals 63.48 and again we have two of the same triangle so no need to half it. So we add the two totals of 126.96 and 63.48 together to get 190.44.
8 5 and 18 8
7 2 9 2
8 - 5 = 3, 8 - 7 = 1, 5 - 2 = 3 and 18 - 8 = 10, 18 - 9 = 9, 9 - 2 = 7, 8 - 2 = 6
To solve this problem, all we have to do is to thoroughly
analyze the situation step by step.
First let us work on the remaining 10 gallons of water in
the tank. We are given that 2 / 3 of the water initially in the tank leaked
out. Therefore this means that we are left with 1 / 3 the original amount of
water which is 10 gallons, hence:
(1 / 3) Vi = 10 gallons
where Vi is the initial volume of water inside the tank,
calculating for Vi:
Vi = 3 (10 gallons)
Vi = 30 gallons
We are also given that this initial volume of water is
just 3 / 4 of the total capacity of the tank, therefore:
(3 / 4) Vc = Vi
where Vc is the volume capacity of the tank, calculating
for Vc:
Vc = 4 Vi / 3
Vc = 4 (30 gallons) / 3
Vc = 40 gallons
Answer:
<span>Capacity of the fish tank is 40 gallons</span>
