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svp [43]
2 years ago
10

The warehouse already has 27 pallets of stock waiting to be unloaded, and the delivery van arrives with another 8. The warehouse

has room for 32 pallets, how many extra pallets will there be?
Mathematics
1 answer:
Natasha_Volkova [10]2 years ago
5 0
To find the answer you would add 27 and 8 together which would give you 35. Once you've done that, you would subtract 32 from 35 which would give you 3 meaning that there will be 3 pallets left over as your answer.
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If 2 tacos and 5 drinks cost $20, And three tacos and five drinks cost $25 how much does a taco cost
san4es73 [151]
A taco costs $5
This is because there was no difference in the cost except for $5. The only item added was one taco. Drinks cost $2 each.
4 0
1 year ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
Given data for different baseball teams’ number of home runs and wins for the past season, how would you find the equation of th
NNADVOKAT [17]
You can get the amount that they get, by getting the amount of home runs vs the amount of wins they won, to show how the homeruns affect the wins

you can have x as the wins, and y by the amount of homeruns per win.

Then you can create first a bar graph, and then a line graph, to show how the homeruns affects the victory

hope this helps
7 0
1 year ago
Read 2 more answers
A person died leaving property worth rs.4000.40. His widow get 0.125 of the property and his son got 0.4 of the remainder. What
belka [17]

Answer:

Widow's Share = Rs 500.05

Son's share = Rs 1400.14

Step-by-step explanation:

Property = 4000.40

Widow get share = 0.125

So, Share of Widow = 0.125 * 4000.40

Widow's Share = Rs 500.05

Remaining Property = 4000.40 - 500.05

Remaining Property = 3500.35

Son's share = 0.4 * 3500.35

Son's share = Rs 1400.14

6 0
1 year ago
M∠1=45° and m∠3=65°
7nadin3 [17]

Answer:

In Right Δ ABC with right angle B,

∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°

∠A+∠B+∠C=180°[∠ sum property of triangle]

3 x-8+90 + x-2=180

Adding and subtracting like terms

4 x-10+90=180

4 x+80=180

4 x=180-80

4 x=100

x=100/4

x=25°

∠A=3×25-8=75-8=67°




6 0
1 year ago
Read 2 more answers
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