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Nadusha1986 [10]
2 years ago
12

A fish tank is three-quarters (3/4) full. two-thirds (2/3) of the water leaks out, leaving 10 gallons of water in the tank. what

is the capacity of the fish tank?
Mathematics
1 answer:
Naily [24]2 years ago
3 0

To solve this problem, all we have to do is to thoroughly analyze the situation step by step.

First let us work on the remaining 10 gallons of water in the tank. We are given that 2 / 3 of the water initially in the tank leaked out. Therefore this means that we are left with 1 / 3 the original amount of water which is 10 gallons, hence:

(1 / 3) Vi = 10 gallons

where Vi is the initial volume of water inside the tank, calculating for Vi:

Vi = 3 (10 gallons)

Vi = 30 gallons

 

We are also given that this initial volume of water is just 3 / 4 of the total capacity of the tank, therefore:

(3 / 4) Vc = Vi

where Vc is the volume capacity of the tank, calculating for Vc:

Vc = 4 Vi / 3

Vc = 4 (30 gallons) / 3

Vc = 40 gallons

 

Answer:

<span>Capacity of the fish tank is 40 gallons</span>

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Side AB of square ABCD is parallel to the Y axis and the perimeter of ABCD is 36. If the coordinates of point B is (5,17) . What
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<h3>Answer: (C) (14,8)</h3>

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a leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that rate, how many gallons of water will the
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You can either scale down so you can get to 48 hours or just multiply from 20 to 48 and I'll explain both ways.
Scaling down:
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20÷5=4; It takes 4 hours to fill it up to one gallon.
You can now divide 48 by 4 to see how many gallons it'll take up to 48 hours.
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Quicker:
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Now multiply since it filled it up to 5 gallons.
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It'll fill 12 gallons in 48 hours.
Tell me if this helps!!
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