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2 years ago

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A man divided $9,000 among his wife, son, and daughter. The wife received twice as much as the daughter, and the son received $1

,000 more than the daughter. How much did each receive?
If x is the amount the wife received, then which of the following expressions represents the amount received by the son?

A. x/2 + 1000
B. x + 1000
C. 2x + 1000

2 answers:

oksian1 [2.3K]2 years ago

5 0

Your answer is A. x/2+1000

the mother recieved $4000 and the son recieved $3000, $4000/2 equals $2000, $2000 plus $1000 equals $3000

hope I helped please thank, rate, and award me best answer if you're on desktop :)

mylen [45]2 years ago

4 0

A.) x/2+1,000. Here is a picture to prove it

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If a linear system has four equations and seven variables, then it must have infinitely many solutions. True or False

Savatey [412]

Answer:

The statement is False.

Step-by-step explanation:

Consider the provided information.

If a linear system has four equations and seven variables, then it must have infinitely many solutions.

We need to determine the above statement is true or false.

The above statement is false, it could be inconsistent, and therefore have no solutions,

For example:

$x_1+x_2+x_3+x_4 +x_5+x_6+x_7=0\\x_1+x_2+x_3 =1\\x_4 +x_5 =1\\x_6+ x_7=1$

Hence, there is no solution.

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2 years ago

Cindy found a collection of baseball cards in her attic worth $8,000. the collection is estimated to increase in value by 1.5% p

Sergio [31]

A]
Exponential function is given by the form:
y=a(b)ˣ
where:
a=initial value
b=growth factor
From the question:
a=$8000, b=1.015,
thus the exponential growth function of this situation is:
y=8000(1.015)ˣ

b] The value of the collection after 7 years will be:
x=7 years
Using the formula:
y=8000(1.015)ˣ
plugging the values we get:
y=8000(1.015)⁷
y=8,878.76

Answer: $8,878.76

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2 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

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By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

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1 year ago

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Important: Please use " ^ " to indicate exponentiation:

<span>"f(x) =x^2 to the number of x-intercepts in the graph of g(x) = x^2 +2."

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</span>

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Maksim231197 [3]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers