Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
£18240
since the amount she earned falls within the range of the tax rate 40%, multiply her earnings by 0.4.
£45600*0.4= 18240
Step-by-step explanation:
0.6/100= 0.006 should be multiplied to decrease by 0.6%
<span>Lois used a credit card to make the purchase.
One can't purchase an item that costs more than the balance in a debit card. The debit card is equivalent to cash on hand. You can only spend what you have.
The credit card is equivalent to a loan. You don't have the money as of the moment but when you use the credit card, you owe the issuing bank the amount you've put on credit. The bank will pay the merchant and you will pay the bank. Interest is an additional expense when you pay your bill beyond the due date. The interest is applied on the amount outstanding upon the payment due date. </span>
Answer: <u>Last option</u>
Step-by-step explanation:
The z-scores give us information about how many standard deviations from the mean the data are. This difference can be negative, if the data are n deviations to the left of the mean, or it can be positive if the data are n deviations to the right of the mean.
To calculate the Z scores, we calculate the difference between the value of the data and the mean and then divide this difference by the standard deviation.
so
.
Where x is the value of the data, μ is the mean and σ is the standard deviation
In this case
:
μ = 12 $/h
= 2 $/h
We need to calculate the Z-scores for 
and 
Then for :
.
Then for :
.
Therefore the answer is:
