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Expand (2x-3y)^4 using Pascal's Triangle. Show work

deff fn [24]

(2x+3y)⁴
1) let 2x = a and 3y = b

(a+b)⁴ = a⁴ + a³b + a²b² + ab³ + b⁴
Now let's find the coefficient of each factor using Pascal Triangle

0 | 1
1 | 1 1
2 | 1 2 1
3 | 1 3 3 1
4 | 1 4 6 4 1

0,1,2,3,4,.. represent the exponents of binomials
Since our binomial has a 4th exponents, the coefficients are respectively:

(1)a⁴ + (4)a³b + (6)a²b² + (4)ab³ + (1)b⁴
Now replace a and b by their real values in (1):

2⁴x⁴ +(4)8x³(3y) + (6)(2²x²)(3²y²) + (4)(2x)(3³y³) + (1)(3⁴)(y⁴)

16x⁴ + 96x³y + 216x²y² + 216xy³ + 81y⁴

3 0

1 year ago

the local volleyball team hosts a concession stand to raise money. They can spend $120 to purchase popcorn, candy, and drinks. t

Art [367]

To solve this question, I did an equation:
0.75x + 1.20y = 120
0.75(95) + 1.20(35) = 120
Then multiply:
71.25 + 42 = 120
Now to check:
71.25 + 42 = 113.25
Answer: 120 - 113.25 = $6.75 Hope this helps

7 0

2 years ago

If two different people are randomly selected from the 884 subjects, find the probability that they are both women. Round to fou

galina1969 [7]

The answer is 0.3274

5 0

1 year ago

If each lap in a pool is 100 meters long, how many laps equal one mile? Round to the nearest tenth. (Hint: 1 foot ≈0.3048 meter)

aalyn [17]

If each lap in a pool is 100 meters long,how many laps equal one mile Round to the nearest tenth.(Hint:1 foot=0.3048 meter) 1 mile = 5280 ft lets do a ratio: 1ft/.3034m = x ft/100m the ft and meters sybols cancel, so 1/.3048 =x/100 so 100/.3038 = x = 329.164 so there are 329.164 ft for every 100 meters to find the number of laps to get to a mile which is 5280, do another ratio 329.164ft/100 m =5280 ft/xm the left side reduces to 3.29164 =5280/x you can compute this and see that 5280/3.29164 = 1604.064 meters 1604.064 meters *1 lap / 100m = 16.04064 laps are required to make a mile

7 0

1 year ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

1 year ago