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Korolek [52]
1 year ago
7

Your Turn

Mathematics
1 answer:
Elza [17]1 year ago
3 0

Answer:

y = 3x + 10

y = 3x + 15

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Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour
Dmitry_Shevchenko [17]

Mario's unit rate is given by 900 miles/hour.

Explanation:

We have been given that Mario walked at a rate of 2/3 miles every 10 minutes.

We have the relation between speed, time and distance, which is given by

\text{Speed}= \frac{\text{Distance}}{\text{Time}}

We have,

Distance = \frac{2}{3} \text{ miles}

Time = 10 minutes

On substituting these values in the above formula, we get

\text{Speed} = \frac{2/3}{10}\\\\ \text{Speed} =\frac{2}{10\cdot 3}\\\\ \text{Speed} =[tex]\frac{1}{15} \text{ miles/min}[/tex]

We have to find the unit rate in mile per hour, so we need to multiply it by 60

Thus, unit rate is given by

\frac{1}{15} \times 60\\ = 4 \text{ miles/hour}

5 0
2 years ago
Assume that Mrs. Giang’s car travels 14 miles on each gallon of gas. If she travels to visit her niece who lives 133 miles away,
frutty [35]
Take the amount 14 MPG (miles per gallon)

Then take the number of miles to go (133 miles to go)

Divide, like so:

133/14
= 9.5





3 0
1 year ago
Read 2 more answers
Each month Liz pays $35 to her phone company just to use the phone. Each text she sends costs her an additional $0.05. In March
olchik [2.2K]
First let's set up an equation: 35+0.05t. 
35 is the phone rate per month plus the number of texts (t) times 0.05 (cost of 1 text)

Now we can find the amount of texts she sent each month.

March
 35+0.05t=72.60
-35               -35
0.05t=37.60
------   -------
0.05    0.05
t=752

April
 35+0.05t=65.85
-35            -35
0.05t=30.85
------   -------
0.05    0.05
t=617

She sent 752 texts in March and 617 texts in April.


7 0
1 year ago
A claim is made that expression 1 and expression 2 are equivalent. A student is asked to provide proof that the claim is true.
finlep [7]

Answer:

The answer is B

5 0
1 year ago
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Naoya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had 350 pages left to re
Ivahew [28]
In 4 hours, Naoya must have read

\dfrac{55\text{ pages}}{1\text{ h}}\cdot4\text{ h}=220\text{ pages}

There were 350 pages remaining at the time, so the total number of pages is 220+350=570.

For each hour of reading, Naoya reads 55 pages, so the number of pages he's finished reading by the t'th hour is 55t. So the number of pages left to read is given by

P(t)=570-55t
6 0
1 year ago
Read 2 more answers
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