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barxatty [35]
2 years ago
14

Caleb draws 14 dogs on each of 4 posters.He draws 18 cats on each of 6 other posters. If he draws 5 more dogs on each poster wit

h dogs, how many dogs ad cats does he draws?
Mathematics
1 answer:
MatroZZZ [7]2 years ago
5 0
Caleb draws 14 dogs on each of 4 posters.
Then,
Number of dogs drawn by caleb in the first instance = (14 * 4) dogs
                                                                                    = 56 dogs
Celeb drew 18 cats on each of 6 other posters.
Then
Number of cats drawn by Caleb in the first instance = (18 * 6) cats
                                                                                   = 108 cats
Again Caleb draws 5 more dogs on each poster with dogs.
Then,
The number of Dogs drwn in the second instance = (5 * 4) dogs
                                                                                 = 20 dogs
So, the total number of dogs drawn by Caleb = ( 56 + 20) dogs
                                                                         = 76 dogs
Then the total number of cats and dogs drawn by Caleb = 108 + 76
                                                                                           = 184
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Alik [6]
45th percentile means that 45% of the data fall below that number while 55% (that is, 100-45) fall above it.

Now, arranging the number in ascending order;
$60, $85, $95, $105, $120, $145, $155, $175, $190, $215, $235, $240, $260, $285, $325

The total number of counts = 15
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Index = 15*45% = 15*0.45 = 6.75

Round up,
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The,
7th number = $155

Therefore, 45th percentile value of the data = $155
8 0
1 year ago
Three brothers share one video game system at their home. In total, they are allowed to play for one half hour each day. If each
o-na [289]

Answer:

45 min.

Step-by-step explanation:

1 1/2 hours = 90 min.

90 min. / 2 brothers = 45 min. each

4 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ANSWER!!
Natasha2012 [34]
Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}

make sure your calculator is in Degree mode.

4 0
2 years ago
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In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,
Elina [12.6K]

Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒  \frac{Sin E}{e} =\frac{Sin  F}{f}

On substituting the values, we get

⇒  \frac{Sin70^{\circ}}{590} =\frac{SinF}{610}

On applying cross multiplication, we get

⇒   SinF=\frac{610\times Sin 70^{\circ}}{590}

On substituting the values, we get

⇒            =\frac{61\times 0.95969262}{59}

⇒            =\frac{57.3212499}{59}

⇒            =0.971546608

now,

⇒  F=Sin^{-1}(0.971546608)

⇒      =76^{\circ}

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2 years ago
Taxes on the property buyer Tamara is purchasing are $8,200, due on December 31. If the closing is set for June 29th, using the
rosijanka [135]

The buyer will be paying taxes for 185 days, so will pay

... (185/365)·$8200 = $4156

Your most appropriate choice seems to be $4178, which corresponds to 186 days' taxes.

_____

There are 30 days in each month in the last half of the year, plus 1 additional day in each of July, August, October, and December. The 30th of June also belongs to the buyer (but the 29th, closing day, does not), so there are 180+5 = 185 days for which the buyer must pay taxes. The answer choices don't include that value.

3 0
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