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2 years ago

The vertex of the parabola is at (-3,-2) which of the following could be its equation

Mathematics

2 answers:

Pepsi [2]2 years ago

7 0

Answer: D;x=-2(y+2)^2-3

Step-by-step explanation: since,(-3,-2) is the vertex of parabola this means that when y=-2, x must be equal to -3

but this is true only in D part

ki77a [65]2 years ago

3 0

D;x=-2(y+2)^2-3 is the equation

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Consider the equation StartFraction x over 5 EndFraction minus 2 = 11, where x represents the number of basketball players that

Free_Kalibri [48]

Answer:

just copy and paste below

Step-by-step explanation:

Step-by-step explanation:Sample Response: The equation could model a scenario determining the number of players on each team in a league of five teams, if 2 players have to be taken out of the possible players to be referees and to keep score. There will be 11 players on each team.

6 0

2 years ago

In ΔXYZ, x = 71 cm, y = 91 cm and z=71 cm. Find the area of ΔXYZ to the nearest square centimeter.

anyanavicka [17]

since its an isoscelies trangle, they probably wanted you to do base times height

make a 71-91/2-x x triangle

where x is the height of the triangle to the base 91 and 71 is the hypothenuse

and then do bh/2

use heron's formula

s= 71+91/2

area= $\sqrt{(71+91/2)(71+91/2-71)(71+91/2-71)(71+91/2-91)}$

have fun solving that

5 0

2 years ago

Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Debora [2.8K]

Option A

$2x^2(6x-1) + 3(6x-1)$ is one way to determine the factors of $12x^3-2x^2+18x-3$ by grouping

Solution:

Factoring by grouping means that you will group terms with common factors before factoring

Given expression is:

$12x^3-2x^2+18x-3$

Group the first two terms together and then the last two terms together.

$(12x^3-2x^2)+(18x-3)$

We can see that $2x^2$ is common in first two terms

And 3 is common in last two terms

Factor them out

$(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)$

$2x^2(6x-1) + 3(6x-1)$

Thus option A is correct

6 0

2 years ago

Read 2 more answers

Which of the following values of x satisfy the equation 3x^2-8x+4=0

igomit [66]

$3x^2-8x+4=0\\\\\Delta=b^2-4ac=(-8)^2-4\times3\times4=64-48=16\\\\x_1=\dfrac{-b+\sqrt{\Delta}}{2a}=\dfrac{8-4}{6}=\dfrac{4}{6}=\dfrac{2}{3}\\\\x_2=\dfrac{-b-\sqrt{\Delta}}{2a}=\dfrac{8+4}{6}=\dfrac{12}{6}=2\\\\\boxed{S=\left\{\dfrac{2}{3};2\right\}}$

6 0

2 years ago

Read 2 more answers

Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce

pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0

2 years ago