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1 year ago

The vertex of the parabola is at (-3,-2) which of the following could be its equation

Mathematics

2 answers:

Pepsi [2]1 year ago

7 0

Answer: D;x=-2(y+2)^2-3

Step-by-step explanation: since,(-3,-2) is the vertex of parabola this means that when y=-2, x must be equal to -3

but this is true only in D part

ki77a [65]1 year ago

3 0

D;x=-2(y+2)^2-3 is the equation

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Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?

In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)= $2x^{3}-26x-24$

$2x^{3}-26x-24$ =0

$2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\$

$=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\$

$=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\$

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

7 0

2 years ago

Read 2 more answers

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

sweet [91]

A conservative vector field $\mathbf f$ has curl $\nabla\times\mathbf f=\mathbf0$ . In this case,

$\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0$

so the vector field is not conservative.

3 0

1 year ago

Which equation can be solved to find one of the missing side lengths in the triangle?

IrinaK [193]

Answer:

it should be D....due to the fact that opposite over adjacent for the missing length

8 0

1 year ago

In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist

vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0

1 year ago

The Helheim glacier in Greenland enters the ocean in a 6.3 kilometer wide fjord. The terminus of the glacier retreated 7.5 kilom

vladimir1956 [14]

Answer:

7.56 km²

Step-by-step explanation:

Given data:

Width of the fjord, w = 6.3 km

Retreated terminus of the glacier between may 2001 and June 2005, d = 7.5 km

thus, the length lost , y = 7.5 - 6.3 = 1.2 km

now, the area is given as:

A = Length × width

on substituting the values, we get

A = 1.2 × 6.3

A = 7.56 km²

Hence, the surface area lost by the glacier in the fjord is 7.56 km²

7 0

2 years ago