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murzikaleks [220]
1 year ago
12

Ben starts walking along a path at 2 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the sam

e path at 7 mi/h. How long (in hours) will it be before Amanda catches up to Ben?
Mathematics
1 answer:
Viefleur [7K]1 year ago
6 0

Answer:

Amanda will catch up Ben after 0.6 hours.

Step-by-step explanation:

Amanda begins jogging along the same path at 7 mi/h.

This means that Amanda's position, after t hours, is given by:

A(t) = 7t

Ben starts walking along a path at 2 mi/h.

Amanda leaves after one and a half hour, which means that Ben will be at position 2*1.5 = 3. So Ben's position after t hours is given by:

B(t) = 3 + 2t

How long (in hours) will it be before Amanda catches up to Ben?

This will happen when:

A(t) = B(t)

So

7t = 3 + 2t

5t = 3

t = \frac{3}{5}

t = 0.6

Amanda will catch up Ben after 0.6 hours.

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