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PIT_PIT [208]
1 year ago
6

The polynomial 24x3 − 54x2 + 44x − 99 is factored by grouping. 24x3 − 54x2 + 44x − 99 24x3 + 44x − 54x2 − 99 4x(____) − 9(____)

What is the common factor that is missing from both sets of parentheses?
Mathematics
1 answer:
Alenkasestr [34]1 year ago
3 0

Answer: 6x^2+11

Step-by-step explanation:

Given the polynomial of degree 3:

24x^3 - 54x^2 + 44x -99

You can observe make two groups or two terms each:

(24x^3 + 44x) - (54x^2 + 99)

The Greatest Common Factor (GCF), is the highest number that divides into two or more numbers without leaving remainder.

 You can observe that the GCF of both set are factored out (4x and 9), then, you can find  the common factor that is missing from both sets of parentheses with this procedure:

(\frac{24x^3}{4x}+\frac{44x}{4x})-(\frac{54x^2}{9}+\frac{99}{9})=(6x^2+11)-(6x^2+11)

You can observe that the common factor that is missing from both sets of parentheses is:

6x^2+11

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Answer:

at x = 10,   4x^{2}  + 17x + 2  = 572

Step-by-step explanation:

The given equation is 4x^{2}  + 17x + 2

Here, lets substitute the value of x = 10

So, the equation simplifies to ,

4 \times (10)^{2}  + 17(10) + 2

= (4 x 100)  + 170 + 2 = 400 + 170 + 2

= 572

So, at x = 10,   4x^{2}  + 17x + 2 = 572

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WILL GIVE BRAINLIEST ANSWER!!
Natasha2012 [34]
Check the picture below.

now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.

and 29' is just 29/60 degrees or about 0.48 degrees.

so 16°23' is about 16.38°, and 49°29' is about 49.48°

\bf tan(16.38^o)=\cfrac{200}{a+b}\implies a+b=\cfrac{200}{tan(16.38^o)}
\\\\\\
\boxed{b=\cfrac{200}{tan(16.38^o)}-a}
\\\\\\
tan(49.48^o)=\cfrac{200}{b}\implies \boxed{b=\cfrac{200}{tan(49.48^o)}}\\\\
-------------------------------\\\\
\cfrac{200}{tan(49.48^o)}=\cfrac{200}{tan(16.38^o)}-a\\\\\\a=\cfrac{200}{tan(16.38^o)}-\cfrac{200}{tan(49.48^o)}

make sure your calculator is in Degree mode.

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Step-by-step explanation:

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purchased of home =$85000

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