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1 year ago

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6 people sharing 40 lbs of gold evenly. How many do they get? Then subtract 1 2/3 from the result of the problem above & sim

plify completely. Please help cause it's not accepting what I have

2 answers:

r-ruslan [8.4K]1 year ago

7 0

Answer: 6

Step-by-step explanation:

Given Data:

Number of people = 6

Amount of Gold to be shared = 40lbs

Subtract 2/3 from your answer.

Therefore

If six people are to share 40lbs of gold evenly

= 40lbs / 6

Divide through by 2

= 20lbs / 3

= 20lbs / 3 - 2/3

= 18/3

= 6

Each person would get approximately 6lbs of gold

umka21 [38]1 year ago

6 0

Answer:

1. Each individual gets $6\frac{2}{3}lb$ of gold

2. After subtracting by $1\frac{2}{3}$ , the result is 5

Step-by-step explanation:

Given

Size of Gold = 40 lbs

Number of people = 6

Required

1. Proportion of each individual

2. Subtract $1\frac{2}{3}$ from each proportion

1. Proportion of each individual

To calculate how many each individuals get (in other words, the proportion of each individual), we simply divide the total size of gold by the number of people

Mathematically,

$Proportion = \frac{Total}{People}$

$Proportion = \frac{40}{6}$

Reduce fraction to lowest term by dividing numerator and denominator by 2

$Proportion = \frac{20}{3}$

Convert to mixed fraction

$Proportion = 6\frac{2}{3}$

Hence each individual gets $6\frac{2}{3}lb$ of gold

2. Subtract $1\frac{2}{3}$ from each proportion

This is represented by

$6\frac{2}{3} - 1\frac{2}{3}$

Convert both fractions to improper fractions

= $\frac{20}{3} - \frac{5}{3}$

Find LCM of both fractions

= $\frac{20 - 5}{3}$

Subtract

= $\frac{15}{3}$

= 5

Hence, after subtracting by $1\frac{2}{3}$ , the result is 5

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Answer:

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Step-by-step explanation:

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I hope it helps you!

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