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2 years ago

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6 people sharing 40 lbs of gold evenly. How many do they get? Then subtract 1 2/3 from the result of the problem above & sim

plify completely. Please help cause it's not accepting what I have

2 answers:

r-ruslan [8.4K]2 years ago

7 0

Answer: 6

Step-by-step explanation:

Given Data:

Number of people = 6

Amount of Gold to be shared = 40lbs

Subtract 2/3 from your answer.

Therefore

If six people are to share 40lbs of gold evenly

= 40lbs / 6

Divide through by 2

= 20lbs / 3

= 20lbs / 3 - 2/3

= 18/3

= 6

Each person would get approximately 6lbs of gold

umka21 [38]2 years ago

6 0

Answer:

1. Each individual gets $6\frac{2}{3}lb$ of gold

2. After subtracting by $1\frac{2}{3}$ , the result is 5

Step-by-step explanation:

Given

Size of Gold = 40 lbs

Number of people = 6

Required

1. Proportion of each individual

2. Subtract $1\frac{2}{3}$ from each proportion

1. Proportion of each individual

To calculate how many each individuals get (in other words, the proportion of each individual), we simply divide the total size of gold by the number of people

Mathematically,

$Proportion = \frac{Total}{People}$

$Proportion = \frac{40}{6}$

Reduce fraction to lowest term by dividing numerator and denominator by 2

$Proportion = \frac{20}{3}$

Convert to mixed fraction

$Proportion = 6\frac{2}{3}$

Hence each individual gets $6\frac{2}{3}lb$ of gold

2. Subtract $1\frac{2}{3}$ from each proportion

This is represented by

$6\frac{2}{3} - 1\frac{2}{3}$

Convert both fractions to improper fractions

= $\frac{20}{3} - \frac{5}{3}$

Find LCM of both fractions

= $\frac{20 - 5}{3}$

Subtract

= $\frac{15}{3}$

= 5

Hence, after subtracting by $1\frac{2}{3}$ , the result is 5

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Answer:

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have that:

A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 49.9 cm and a standard deviation of 3.74 cm, so $\mu = 49.9, \sigma = 3.74$ .

What is the length in cm of the longest 15% of Atlantic cod in this area?

We have to find the value of X for the value of Z that has a pvalue of 0.85.

Looking at the zscore table, we have that Z = 1.04 has a pvalue of 0.8508. So, we have to find the value of X when $Z = 1.04, \mu = 49.9, \sigma = 3.74$ .

So

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 49.9}{3.74}$

$X - 49.9 = 3.8896$

$X = 53.7896$

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

8 0

2 years ago

A machine only accepts 25₵ coins.

Umnica [9.8K]

Answer:

15.

Step-by-step explanation:

3.75 / 25 = 15.

3 0

2 years ago

Read 2 more answers

Using Normal Distribution to Analyze Data Martin suspects that people carry less cash with them than they used to because of cre

jek_recluse [69]

Answer:

Step-by-step explanation:

Sample size = 95

X=cash carried by the persons

x bar = 8.00

s = sample std dev = 2.50

Std error = $\frac{s}{\sqrt{n} } =\frac{2.5}{\sqrt{95} } \\=0.2565$

Hence Z score would be

$\frac{x-8}{0.2565}$

$a) P(X$

-0.00

b) $P(9$

c) 95% conf interval margin of error = ± $1.96*0.2565$

=±0.54782

Confi interval = (8-0.5027, 8+0.5027)

= (7.4923, 8.5027)

C)If conf level increases, then width of interval would increase since critical value would increase.

If sample size increases std error would decrease and hence margin of error.

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3 0

2 years ago

Andre ran 2 kilometers in 15 minutes, and Jada ran 3 kilometers in 20 minutes. Both ran at a constant speed. Did they run at the

Goshia [24]

Answer:

speed of Jada = 6km per hour which is not equal to

speed of Andre = 8km per hour

They did not run at same speed

Step-by-step explanation:

formula of speed = distance covered/ time taken

For Andre

Distance = 2 KM

time = 15 mins

60 mins = 1 hour

15 mins = 1/60 * 15 hour = 0.25 hours

thus,

speed = 2km/0.25 hour = 8 km per hour

Similarly for Jada

Distance = 3 KM

time = 20 mins

60 mins = 1 hour

20 mins = 1/60 * 20 hour = 1/3 hours

thus,

speed = 2km/(1/3)hour = 6 km per hour

Now we have

speed of Jada = 6km per hour which is not equal to

speed of Andre = 8km per hour

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2 years ago

Find the coordinates of the midpoint of LB if L(8,5) and B(-6,2)<br><br> 10 points!!!

KATRIN_1 [288]

Answer:

A, (1, 3+1/2)

Step-by-step explanation:

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Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}

Now we simplify using PEMDAS. First step is parentheses.

m= {2/2, 7/2}

Simplifying again (and making 7/2 a mixed number), it becomes

m= {1, 3+1/2}

Hope this helps!

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1 year ago