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2 years ago

The table shows the cost of a taxicab ride for several driving distances.

Mathematics

1 answer:

s2008m [1.1K]2 years ago

7 0

Answer:

oops didnt mean to click answer again

Step-by-step explanation:

so it asked me go through the verification and yk how it be hella irriuitating kuz all im tryna do is

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a rectangle rug has a perimeter of 146 ft the width of the rug is 5 feet more than three times the length find the length and th

dem82 [27]

Answer:

The length = 56 feet and the width = 17 feet.

Step-by-step explanation:

We can set up 2 equations to solve this. Let the length of the rug be x, then

x = 3w + 5 where w = the width. ( looks like you got the width and the length mixed up. The length is the longest side)

The perimeter = 2x + 2w = 146 so we have the 2 equations:

x = 3w + 5

2x + 2w = 146

Now we substitute for x in the second equation:

2(3w + 5) + 2w = 146

6w + 10 + 2w = 146

8w = 136

w = 17 feet,

and x = 3(17) + 5 = 56 feet.

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2 years ago

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Marianne has been collecting donations for her biscuit stall at the school summer fayre. There are some luxury gift tins of bisc

Marta_Voda [28]

I don't know what 10p is so before I answer I'd have to know what that is

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2 years ago

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A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical

Korolek [52]

Answer:

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

Total outcomes:

100 customers

Desired outcomes:

A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.

Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?

$p = \frac{78}{100} = 0.78$

78% probability that a randomly selected online customer does not live within 50 miles of a physical store.

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2 years ago

francesca wants to give one of her photographs to a friend as a gift. help her choose the photograph and determine the style and

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2 years ago

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores o

otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So $X = 52, \mu = 70, \sigma = 11$