Answer:
Option B - 
and 
Step-by-step explanation:
Given : The Thrill amusement park charges an entry fee of $40 and an additional $5 per ride, x. The Splash water park charges an entry fee of $60 and an additional $3 per ride, x.
To find : Which system of equations could be used to determine the solution where the cost per ride of the two amusement parks, y, is the same?
Solution :
Let x be the number of rides and
y be the cost per ride.
According to question,
The Thrill amusement park charges an entry fee of $40 and an additional $5 per ride.
The equation form is 
The Splash water park charges an entry fee of $60 and an additional $3 per ride.
The equation form is 
Therefore, The required system of equations form are
and
So,Option B is correct.
Answer:
Step-by-step explanation:
Answer: it would take 20 weeks before the amount in both accounts would be the same.
Step-by-step explanation:
Let x represent the number of weeks that it will take either Ruben and Shawna to have the same amount of money in their account.
Let y represent the total amount that would be in Shawna's account after x weeks
Let z represent the total amount that would be in Ruben's account after x weeks
Shawna has $750 in the bank. She deposits $37.50 each week. This means that the total amount after x weeks would be
y = 37.5x + 750
Ruben has $850 in the bank. He deposits his paycheck of $102.75 every Monday,and he spends about $70.25 each week.. This means that the total amount after x weeks would be
z = 850 + 102.75x - 70.25x
z = 850 + 32.5x
To determine the number of weeks before the amount in both accounts will becomes the same, we would equate y to z. It becomes
37.5x + 750= 850 + 32.5x
37.5x - 32.5x = 850 - 750
5x = 100
x = 100/5 = 20
Speed= 100 rev/1 min=(1/4rev)/x min
x=(1/400)min=60/400 sec=3/20=0.15 sec
Answer:
His 95% confidence interval is (0.065, 0.155).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
His 95% confidence interval is (0.065, 0.155).
Compab=a.b/|a|
b=<0,1,−2√10>
a.b= 2√10
|a| = √10
a.b/|a|=2√10 / √10=2
