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belka [17]
2 years ago
13

1/3 of Murka’s age is twice as much as Ivan’s age. What is the ratio of Murka’s age to Ivan’s age?

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0
Let these two ages be i and m.  Then (1/3)m = 2i, which becomes m = 6i when we multiply both sides by 3.

Ratio:

M's age      6i
---------- = ------ = 6
I's age         i

M is 6 times older than Ivan.

<span>The ratio of M's age to Ivan's is 6:1, or just 6.


</span>
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