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belka [17]
2 years ago
13

1/3 of Murka’s age is twice as much as Ivan’s age. What is the ratio of Murka’s age to Ivan’s age?

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0
Let these two ages be i and m.  Then (1/3)m = 2i, which becomes m = 6i when we multiply both sides by 3.

Ratio:

M's age      6i
---------- = ------ = 6
I's age         i

M is 6 times older than Ivan.

<span>The ratio of M's age to Ivan's is 6:1, or just 6.


</span>
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what is the simplified form of the following expression? Assume x is greater than or equal to 0 and y is greater than or equal t
yarga [219]

the given expression is :

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4 0
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Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

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QED

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