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seropon [69]
2 years ago
13

If john can drink one barrel of water in 6 days, and mary can drink one barrel of water in 12 days, how long would it take them

to drink one barrel of water together?
Mathematics
1 answer:
krek1111 [17]2 years ago
6 0
Hello,

A good first step to take would be to calculate how much of a barrel John and Mary can drink together in 1 day.


If John can drink 1 barrel in 6 days, then every day he can drink 1/6 of a barrel.
If Mary can drink 1 barrel in 12 days, then every day she can drink 1/12 of a barrel. 

Every day, the total that John and Mary can drink will be (1/6) + (1/12) = (1/4) of a barrel.

If we want to know how many days it will take for them to drink 1 barrel of water together, and they drink 1/4 of a gallon every day, we do 

(1) / (1/4) = 1 * (4/1) = 4 days

It will take 4 days for John and Mary to drink 1 barrel together.

Hope this helps!


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1) Proiectiile catetelor unui triunghi dreptunghic pe ipotenuza au lungimile 9 cm si 25 cm. Aflati lungimea inaltimii din varful
Flauer [41]

Answer:

1) 15cm

2) left projection/h = h/right projection

Step-by-step explanation:

Question:

1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.

2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.

Solution

1) The length of the height of a right angle triangle is also called the altitude.

Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.

The projections of the legs are 25cm and 9cm.

Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm

In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the

geometric mean of these two segments (the two projections) and it's given by:

left projection/h = h/right projection

AD/h = h/DB

25/h = h/9

Cross multiply

h^2 = 25×9

h =√225 = 15cm

The length of the height at the top of the triangle = 15cm

2) Length of hypotenuse = 34

From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.

There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.

To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.

left projection/h = h/right projection

To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.

Hypotenuse =34cm

Hyp/leg = leg/part

To find leg y, part for leg y = 25cm

34/y = y/25

y^2 = 34×25 = 850

y = √850 = 29.2cm

To find leg x, part for leg x = 9cm

34/y = y/9

y^2 = 34×9 = 306

y = √306 = 17.5cm

8 0
1 year ago
The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1
AlexFokin [52]

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = 2, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = 2

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = x+1, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = x+1

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

7 0
2 years ago
An ice cream store has two new flavors: Fantasy and Ecstasy. Each barrel of Fantasy requires 4
Y_Kistochka [10]

Answer:

  • Fantasy: 3 barrels
  • Ecstasy: 1 barrel

Step-by-step explanation:

<u>Given</u>

  Fantasy uses 4 lb of nuts, 3 lb of chocolate, for a profit of $50

  Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40

  In stock are 16 lb of nuts, 10 lb of chocolate

<u>Find</u>

 amount of each to maximize profit

<u>Solution</u>

Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...

  4x +4y ≤ 16 . . . lb of nuts

  3x +y ≤ 10 . . . . lb of chocolate

We want to maximize

  50x +40y

The graph shows the feasible region. Its vertices are ...

  (0, 4), (3, 1), (3.33, 0)

Profit is maximized at $190 when production is 3 barrels of Fantasy and 1 barrel of Ecstasy.

8 0
1 year ago
Given the functions f(x) = 7x + 13 and g(x) = x + 2, which of the following functions represents f[g(x)] correctly?
LenKa [72]

Answer:

B. f(g(x)) = 7x + 27

Step-by-step explanation:

We have, f(x) = 7x+13 and g(x) = x+2.

So, the function f(g(x)) is obtained by substituting the function g(x) = x+2 in f(x) = 7x+13,

i.e. f(g(x)) = f(x+2)

i.e. f(g(x)) = 7 × (x+2) + 13

i.e. f(g(x)) = 7x + 14 + 13

i.e. f(g(x)) = 7x + 27

Thus, f(g(x)) = 7x + 27

Hence, option B is correct.

4 0
2 years ago
Read 2 more answers
Please solve this equation
Darya [45]

Answer: if you simplify the equation, your answer should be 16

Step-by-step explanation: Simplify  2+22+22+2  to  444.

8÷2×48\div 2\times 48÷2×4

2

Simplify  8÷28\div 28÷2  to  444.

4×44\times 44×4

3

Simplify.

16

4 0
2 years ago
Read 2 more answers
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