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2 years ago

Which of the following notations correctly describe the end behavior of the polynomial graphed below?

Mathematics

1 answer:

algol132 years ago

4 0

The right answer is C

Let me to explain. From the graph we know that the vertex of this parabola is $V(0,8)$ . This is a maximum y-value. We also know that the parabola opens downward, so the leading coefficient is negative. Given that the function is even and the leading coefficient is negative, it follows that the graph falls to the left and right. In a mathematical language this is:

$x \rightarrow -\infty, f(x) \rightarrow -\infty \\ \\ x \rightarrow \infty, f(x) \rightarrow -\infty$

You might be interested in

Find c1 and c2 such that M2+c1M+c2I2=0, where I2 is the identity 2×2 matrix and 0 is the zero matrix of appropriate dimension.

Katyanochek1 [597]

The question is missing parts. Here is the complete question.

Let M = $\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$ . Find $c_{1}$ and $c_{2}$ such that $M^{2}+c_{1}M+c_{2}I_{2}=0$ , where $I_{2}$ is the identity 2x2 matrix and 0 is the zero matrix of appropriate dimension.

Answer: $c_{1} = \frac{-16}{10}$

$c_{2}=\frac{-214}{10}$

Step-by-step explanation: Identity matrix is a sqaure matrix that has 1's along the main diagonal and 0 everywhere else. So, a 2x2 identity matrix is:

$\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

$M^{2} = \left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]$

$M^{2}=\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]$

Solving equation:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+c_{1}\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right] +c_{2}\left[\begin{array}{cc}1&0\\0&1\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$

Multiplying a matrix and a scalar results in all the terms of the matrix multiplied by the scalar. You can only add matrices of the same dimensions.

So, the equation is:

$\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+\left[\begin{array}{cc}6c_{1}&5c_{1}\\-1c_{1}&-4c_{1}\end{array}\right] +\left[\begin{array}{cc}c_{2}&0\\0&c_{2}\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]$

And the system of equations is:

$6c_{1}+c_{2} = -31\\-4c_{1}+c_{2} = -15$

There are several methods to solve this system. One of them is to multiply the second equation to -1 and add both equations:

$6c_{1}+c_{2} = -31\\(-1)*-4c_{1}+c_{2} = -15*(-1)$

$6c_{1}+c_{2} = -31\\4c_{1}-c_{2} = 15$

$10c_{1} = -16$

$c_{1} = \frac{-16}{10}$

With $c_{1}$ , substitute in one of the equations and find $c_{2}$ :

$6c_{1}+c_{2}=-31$

$c_{2}=-31-6(\frac{-16}{10} )$

$c_{2}=-31+(\frac{96}{10} )$

$c_{2}=\frac{-310+96}{10}$

$c_{2}=\frac{-214}{10}$

For the equation, $c_{1} = \frac{-16}{10}$ and $c_{2}=\frac{-214}{10}$

6 0

2 years ago

A florist gathered data about the weekly number of flower deliveries he made to homes and to businesses for several weeks. He us

shutvik [7]

Answer:

The number of deliveries that are predicted to be made to homes during a week with 50 deliveries to business is 87 deliveries

Step-by-step explanation:

The data categorization are;

The number of home deliveries = x

The number of delivery to businesses = y

The line of best fit is y = 0.555·x + 1.629

The number of deliveries that would be made to homes when 50 deliveries are made to businesses is found as follows;

We substitute y = 50 in the line of best fit to get;

50 = 0.555·x + 1.629 =

50 - 1.629 = 0.555·x

0.555·x = 48.371

x = 48.371/0.555= 87.155

Therefore, since we are dealing with deliveries, we approximate to the nearest whole number delivery which is 87 deliveries.

4 0

2 years ago

mark has a cabinet door in his kitchen with the dimensions shown below. he creates a scale drawing where the width of the cabine

laiz [17]

Answer:

$h^{*} = 25\,in$

Step-by-step explanation:

Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:

$n = \frac{15\,in}{3\,ft}$

$n = 5\,\frac{in}{ft}$

The height of the cabinet is:

$h^{*} = n \cdot h_{door}$

$h_{*} = \left(5\,\frac{in}{ft} \right)\cdot (5\,ft)$

$h^{*} = 25\,in$

6 0

2 years ago

Read 2 more answers

Every morning I take either bus number 5 or bus number 8 to work. Every morning the waiting time for the number 5 is exponential

Simora [160]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

3 0

2 years ago

The speed of light is 3 x 108 m/s. If its frequency is 4.11 x 104 Hz, what is its wavelength?

QveST [7]

Answer:

Wave length = speed / frequency

Wave length = 3x10^8 / 4.11x10^4

Wave length = 7.299x10^3nm

Step-by-step explanation:

5 0

2 years ago