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vazorg [7]
2 years ago
13

A washer contains a drum that spins at 750 revolutions per minute. To the nearest hundredth, the angular velocity of the drum is

_____ radians per second.
Mathematics
1 answer:
LenaWriter [7]2 years ago
8 0
For this case, the first thing we must do is to take into account the following transformation of units:
 1 revolution = 2pi radians
 1 minute = 60 seconds
 Applying the transformation of units we have:
 (750) * (1/60) * (2 * pi) = 78.54 rad / sec

 Answer:
 
To the nearest hundredth, the angular velocity of the drum is 78.54 radians per second.
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ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are (x_{1},y_{1}) and (x_{2},y_{2}), then x=\frac{x_{1}+x_{2}}{2} and  y=\frac{y_{1}+y_{2}}{2}

∵ JL is a segment

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∴  x_{2} = -4 and  y_{2} = 3

Lets use the rule above to find the mid-point of JL

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∵ y=\frac{1+3}{2}=\frac{4}{2}

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

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2 years ago
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creativ13 [48]

Answer:

B is the answer.

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Great Job! they are all correct.  :)


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Step-by-step explanation:


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