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2 years ago

13

A washer contains a drum that spins at 750 revolutions per minute. To the nearest hundredth, the angular velocity of the drum is

_____ radians per second.

1 answer:

LenaWriter [7]2 years ago

8 0

For this case, the first thing we must do is to take into account the following transformation of units:
1 revolution = 2pi radians
1 minute = 60 seconds
Applying the transformation of units we have:
$(750) * (1/60) * (2 * pi) = 78.54 rad / sec
$
Answer:
To the nearest hundredth, the angular velocity of the drum is 78.54 radians per second.

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Find the missing side.

Alona [7]

Answer:

9

Step-by-step explanation:

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2 years ago

A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall

avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

$P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625$

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

$P(A \cap B) = 0.125\frac{1}{7} = 0.0179$

What is the probability that today is Monday?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286$

0.0286 = 2.86% probability that today is Monday.

4 0

2 years ago

Clint is in study hall reading the hunger games after 20 minutes he is on page 151 after 45 minutes he's on page 181 how many pa

Mademuasel [1]

After 20 minutes Clint is on page = 151

After 45 minutes Clint is on page = 181

Time slot = $45-20=25$ minutes

Difference in pages in 25 minutes = $181-151=30$ pages.

Lets suppose Clint is reading each page at same pace.

So , In 25 minutes, he can read = 30 pages

In 1 minute he can read = $\frac{30}{25}=1.2$ pages

Initial time is 20 minutes, so he can read the number of pages in 20 minutes = $20\times1.2=24$

So, number of pages Clint read prior to study hall were =

$151-24=127$ pages.

6 0

2 years ago

The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a

maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

$\text{P(green swordtail)}=\dfrac{4}{7}$

Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

$\text{P(Male fish)}=\dfrac{36+24}{140}$

$\text{P(Male fish)}=\dfrac{60}{140}$

$\text{P(Male fish)}=\dfrac{3}{7}$

Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

C. We have to find the probability that the selected fish is a male green swordtail.

$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

4 0

2 years ago

The picture below shows a box sliding down a ramp:

Gennadij [26K]

Answer:

$AC=15.1\ ft$

Step-by-step explanation:

we know that

In the right triangle ABC

The function sine of angle 68 degrees is equal to divide the opposite side SB by the hypotenuse AC

so

$sin(68\°)=\frac{AB}{AC}$

substitute the values and solve for AC

$sin(68\°)=\frac{14}{AC}$

$AC=\frac{14}{sin(68\°)}$

$AC=15.1\ ft$

4 0

2 years ago