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fiasKO [112]
2 years ago
9

Describe how to use the formula C = StartFraction 5 Over 9 EndFraction (F minus 32) to find

Mathematics
1 answer:
MArishka [77]2 years ago
7 0

Answer:

Answer is below

Step-by-step explanation:

C = 5/9(F - 32)        This equation is used to convert from Fahrenheit to Celsius on the temperature scale.

An example is listed below

C = 5/9(32 - 32)             Subtract in the parentheses

C = 5/9(0)                       Multiply

C = 0                       When it is 32 degrees Fahrenheit, it is 0 degrees Celsius

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Answer: 40 degrees

Step-by-step explanation:

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2 years ago
the community food bank has 750 meals to distribute over a 12 hour period. They need to save at least 50 of the meals for the vo
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Since we must save 50 meals for volunteers, the real amount we are giving away is 700 meals in 12 hours.

700/12 = 58.3333...

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Since we can't serve 1/3 of a person, we take 583. Hope this helps!
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2 years ago
Meghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount of th
kupik [55]

Answer:

67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount

Step-by-step explanation:

4 0
2 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
2 years ago
Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data
Bad White [126]

Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

Interquartile range =3

City B

Maximum - Minimum = 18.5

Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

7 0
2 years ago
Read 2 more answers
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