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Nuetrik [128]
1 year ago
9

A) The ratio 20 minutes to 1 hour can be written in the form 1:n.

Mathematics
1 answer:
Fudgin [204]1 year ago
7 0

Answer:

a) 1:3

b) 9:225,000

Step-by-step explanation:

A)

1 hour is equal to 60 minutes. Written as a fraction it would look like

\frac{20}{60} which would be equal to \frac{1}{3}, or 1:3

B)

Just multiply both sides of the ratio by 9, you will get 9:225,000

Hope I helped, please mark as brainliest! Have a good day!

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Step-by-step explanation:

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Please help. I am getting in trouble so please try to be correct...
vichka [17]

Answer: The answer is A 17in2

Step-by-step explanation:

In the question it states that the triangles are congruent (both the same).

  first I found the area of the top orange triangle.

the formula to find the area of a triangle is \frac{1}{2} bh (base times Height).

so I did  \frac{1}{2} 3.23* 5.12  which gave me 8.27.

Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.

the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)

7 0
1 year ago
An office worker can type at the rate of 57 words per minute. Which equation could be used to solve for the number of words he c
8_murik_8 [283]
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4 0
2 years ago
Read 2 more answers
Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
Oduvanchick [21]

Answer:

30 u^{2}

Step-by-step explanation:

The computation of the area of kite ABCD is shown below:

Given data

AC = 10 ;

BD = 6

As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal

Now the area of quadrilateral when the diagonals are given

So, it is

\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}

where,

d_{1}=10\ and\ d_{2}=6

So, the area of the quadrilateral is

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4 0
1 year ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3\frac{1}4 mi, charges = $4.40

So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

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The distance of 3\frac{1}8 miles lies within the range 3 mi - 3\frac{1}4 mi.

So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

6 0
2 years ago
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