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alexandr1967 [171]
1 year ago
11

A dentist wants to find out how often her patients floss their teeth. Which samples are biased? Check all that apply. all her pa

tients patients with no cavities patients younger than 18 every 20th patient every patient with braces
Mathematics
2 answers:
natta225 [31]1 year ago
8 0

Answer: the answers are options B,C,and E or

patients with no cavities

patients younger than 18

every patient with braces

Step-by-step explanation: i got them right on edge

ArbitrLikvidat [17]1 year ago
7 0

Answer:

all her patients patients with no cavities

patients younger than 18

every patient with braces

Step-by-step explanation:

when a sample is selected in a manner that some elements, in this case patients, of population have higher or lower probability of sampling then that sample is biased.

From given case, all the following are biased samples

all her patients patients with no cavities

patients younger than 18

every patient with braces

because they are non-random sample of a population in which all other elements were not equally likely to be chosen!

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Shane, Cheryl, and Isaac went to the store to buy school supplies. Shane bought 4 pens, 3 folders, and 2 notebooks for a total o
vladimir1956 [14]

Answer: 3.00

Step-by-step explanation:

8 0
1 year ago
Aubrey and Charlie are driving to a city that is 120 miles from their house. They have already traveled 20 miles, and they are d
mario62 [17]

Answer:

f(1.5) = _95_

The value indicates that after_1.5 hours_

hours of driving, Aubrey and Charlie will be_95_

miles from home.

Step-by-step explanation:

8 0
1 year ago
Sophia was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a $5 bill
borishaifa [10]
The first thing we will do in this case is to define variables:
 x = number of individual tickets.
 y = number of tickets per couple.
 We have then that the system of equations that represents the problem is:
 10x + 15y = 590
 x + 2y = 68
 Solving the system we have:
 x = 32
 y = 18
 Substituting we have:
 10 (32) + 15 (18) = 590
 320 + 270 = 590
 590 = 590
 Equality is met, therefore the $ 5 bill belongs to the box.
 Answer:
 
the $ 5 bill belong inside the cash box
4 0
2 years ago
Monica has a bag of marbles. There are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick
natima [27]

Answer:

\frac{7}{64}\approx 0.11

Step-by-step explanation:

We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.

Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.          

Since the probability of two independent compound events is always the product of probabilities of both events.

P(\text{A and B})=P(A)*P(B)

Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.

P(Red)=\frac{\text{Total red marbles}}{\text{Total marbles}}

P(Red)=\frac{4}{16}

Probability of picking blue ball out of 16 (4+7+5) marbles:

P(Blue)=\frac{\text{Total blue marbles}}{\text{Total marbles}}

P(Blue)=\frac{7}{16}

Now let us find probability of Monica picking a red and then a blue marble.

P(\text{Red and Blue})=\frac{4}{16}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{1}{4}\times \frac{7}{16}

P(\text{Red and Blue})=\frac{7}{4*16}

P(\text{Red and Blue})=\frac{7}{64}

P(\text{Red and Blue})=0.109375\approx 0.11

Therefore, the probability of picking a red and then blue marble is \frac{7}{64}\approx 0.11.  

7 0
1 year ago
Consider a data set with at least three data values. Suppose the highest value is increased by 10 and the lowest is decreased by
bulgar [2K]

Answer:

a. Mean doesn't change.

b. Median doesn't change.

c. Mode can change.

Step-by-step explanation:

Let us assume the data set with 10 observations

{2,6,4,3,2,6,4,9,4,7}.

Arranging data set in ascending order

{2,2,3,4,4,4,6,6,7,9}

mean=2+2+3+4+4+4+6+6+7+9/10=4.7

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Mode

The most repeated value is 4. So, mode is 4 for assumed data.

Increasing highest value by 10 and decreasing lowest value by 10

{-8,2,3,4,4,4,6,6,7,19}

a.

mean=-8+2+3+4+4+4+6+6+7+19/10=4.7

Mean doesn't change

b.

median

n/2=10/2=5 is an integer so,

median= average of n/2 and n/2 +1

median= (5th value+6th value)/2

median=(4+4)/2=8/2=4

Median doesn't change

c.

Most occurring value is still 4. But mode can change if the value the highest value becomes most concurring value.

5 0
2 years ago
Read 2 more answers
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