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Luba_88 [7]
2 years ago
10

4 7/9 divided by 1 7/12

Mathematics
1 answer:
sesenic [268]2 years ago
6 0

Answer:

2 19/5

Step-by-step explanation:

4 7/9 ÷ 1 7/12

<em>start by turning them into improper fraction by multiplying the denominator to the whole number and adding the product to the numerator , you will get :</em>

42/9 ÷ 17/12

42/9 * 12/17 <em>( reciprocal )</em>

42/3 * 4/17 <em>(9 and 12 can be cut smaller because both are in 3's table)</em>

= <u>172/51</u>

turn this into mixed fraction by -

<em>Divide the numerator by the denominator. </em>

<em>Write down the whole number answer </em>

<em>Then write down any remainder above the denominator</em>

you will get = <u>2 19/5</u>

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The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If
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Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

p=1-e^{-mt}

You know that:

The number of  customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

m=6

As the problem asked for the probability that  a costumber will be on hold less than 30 minutes, we know that:

t=0.5

Substitute the values above into the formula.

Then, you obtain:

p=1-e^{-(6)(0.5)}=0.95 or 95%

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2 years ago
The quotient of 38 times a number and -4
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Answer:

140y

Step-by-step explanation:

35 times a number times -4 is 35×y×(-4) which is -140y

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1 year ago
The graph shows the location of Grant's, Hannah's, and Isobel's houses. Each unit on the graph represents 1 block. A coordinate
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2 years ago
A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
2 years ago
Find the percent of change. Round to the nearest tenth, if necessary.
S_A_V [24]

Answer:

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divide the second number by the first. then do one minus that number

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