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faust18 [17]
2 years ago
10

2 ratios equivalent to 3:12

Mathematics
2 answers:
Hatshy [7]2 years ago
6 0

Answer: 1 : 4 and 2 : 8

Step-by-step explanation: To find 2 different ratios that are equal to the ratio 3:12, we first rewrite the ratio 3:12 as the fraction 3/12. Notice that we can find 1 of our equal ratios by simply writing this fraction in lowest terms. if we divide both the numerator and denominator of 3/12 by their greatest common factor of 3, we get the equal ratio 1/4.

Now we can use 1/4 to find another equal ratio. If we multiply both the numerator and denominator of 1/4 by 2, we get the equal ratio 2/8.

Finally, remember to write these ratios using the same form as the original problem. 1 : 4 and 2 : 8.

Alborosie2 years ago
3 0

Answer:

6:24

12:48

Step-by-step explanation:

3 : 12  

 x2

6:24

 x2

12:48

:)

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The area of an extra large circular pizza from Gambino's Pizzeria is 484\pi \text{ cm}^2484π cm 2 484, pi, space, c, m, start su
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The diameter of an extra large pizza from Gambino's Pizzeria is 44\ cm

Step-by-step explanation:

we know that

The area of a circle (circular pizza ) is equal to

A=\pi r^{2}

we have

A=484\pi\ cm^{2}

substitute in the formula and solve for the radius r

484\pi=\pi r^{2}

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484=r^{2}

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Let number of caps =x

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Since amount cannot be greater than 1000 , so

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Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

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P(A) = 0.8x + 0.25*0.2x = 0.85x

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0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

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1 year ago
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