<span>The correct answer is 'callable certificate of deposit’. Financial institutions can recall these before they reach maturity. This avoids financial institutions having to pay more if interest rates go down.</span>
Answer:
The answer is D or "Brenda is not correct because the equation should be Negative 2 times 8 + (negative 320) = negative 336"
Step-by-step explanation:
I took the quiz!
Answer:
Simplified base would be 3∛4
Step-by-step explanation:
Given exponential function,
![f(x)=\frac{1}{4}(\sqrt[3]{108})^x](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B4%7D%28%5Csqrt%5B3%5D%7B108%7D%29%5Ex)
Since, in an exponential function 
b is called base.
∵ 108 = 2 × 2 × 3 × 3 × 3,
Or 108 = 4 × 3³,
![\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%5B3%5D%7B108%7D%20%3D%20%5Csqrt%5B3%5D%7B4%5Ctimes%203%5E3%7D)
![\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%20%5Csqrt%5B3%5D%283%5E3%29)
( Using ![\sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Ctimes%20%5Csqrt%5Bn%5D%7Bb%7D)
)
![\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%20%283%5E3%29%5E%5Cfrac%7B1%7D%7B3%7D)
![\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D%5Csqrt%5B3%5D%7B4%7D%5Ctimes%203%5E%7B3%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%7D)
( Using power of power property of exponent )
![\sqrt[3]{108}=3\sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B108%7D%3D3%5Csqrt%5B3%5D%7B4%7D)
Hence, the required simplified base would be 3∛4
i.e. SECOND option is correct.
Answer:
The answer would be 12 because you would do 44 divided by 3 2/3
The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
<span>a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds
b]</span><span> What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)</span>²+48(1.5)+6
h(1.5)=42 fee
