Answer:
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 22
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0739
The margin of error is:
M = T*s
In which s is the standard deviation of the sample.
In this question:
s = 3.
Then
M = 2.0739*3 = 6.22
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
Answer: Nice
This text exists to bypass Brainly's 20 character limit.
Answer:
Step-by-step explanation:
the correct answer is B on Edgen. :)
Answer:
x=
Step-by-step explanation:
Step 1: Multiply both sides by x,
gx=−c+x
Step 2: Add -x to both sides.
gx+−x=−c+x+−x
gx−x=−c
Step 3: Factor out variable x.
x(g−1)=−c
Step 4: Divide both sides by g-1.

x=
Hope this helps!
13. it's > because 18,000g = 18kg and that's greater
14.8.456L = 8456ml so it's < 9L
15.2m = 200cm which is < 275cm