All categories

2 years ago

What is the simplified form of 3 StartRoot 135 EndRoot?

Mathematics

2 answers:

jek_recluse [69]2 years ago

5 0

Answer:

$9 \sqrt{135}$

Step-by-step explanation:

Express 135 as a product of 15 and 9:

$135=15*9$

So:

$3\sqrt{15*9}$

Now, use the following property:

$\sqrt[n]{a*b} =\sqrt[n]{a}\hspace{3} \sqrt[n]{b}$

Therefore:

$3\sqrt{15} \sqrt{9}$

Since the square root of 9 is 3, the simplified form of $3\sqrt{135}$ :

$3\sqrt{15} \sqrt{9}=3*3\sqrt{15} =9\sqrt{15}$

svetoff [14.1K]2 years ago

3 0

$\bf 3\sqrt{135}~~ \begin{cases} 135=&3\cdot 3\cdot 15\\ &3^2\cdot 15 \end{cases}\implies 3\sqrt{3^2\cdot 15}\implies 9\sqrt{15}$

You might be interested in

luke paid 30 percent less for a used car than its original price of $3,500. how much did luke pay for the car?

serg [7]

Answer:

Im not sure ok

Step-by-step explanation:

Im trying to solve too

5 0

1 year ago

Read 2 more answers

The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig

Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

= 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

7 0

2 years ago

Read 2 more answers

or the past 50 days, daily sales of laundry detergent in a large grocery store have been recorded (to the nearest 10). Units Sol

bagirrra123 [75]

Answer, step-by-step explanation:

A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:

units sold. relative frequency. Acumulative frequency. interval of random numbers

30. 0.16. 0.16. 0.00 <0.16

40. 0.24. 0.4. 0.16 <0.4

50. 0.3. 0.7. 0.4 <0.7

60. 0.2. 0.9. 0.7<09

70. 0.1. 1. 0.9<1

B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:

random Units

number. sold

0.12. 30

0.96. 70

0.53. 50

0.80. 60

0.95. 70

0.10. 30

0.40. 50

0.45. 50

0.77. 60

0.29. 40

the two lists are compared so that opposite each one is the result of the simulation

3 0

1 year ago

Tracy used the expression (25.6) (16.2) + (25.6) (36.5) + (16.2) (37.8) to find the surface area, in square centimeters, of the

Deffense [45]

So 25.6 + 16.2 + 25.6 + 36.5 + 16.2 + 37.8 = 1961.48

I would say the second statement would best describe her work, because it is giving the most detail out of those statements.

Hope this helps!

~Jarvis

3 0

2 years ago

Read 2 more answers

The Lynx pay their four running backs $1 million, $850,000, $750,000, and $500,000. If the team salary is $33 million a year, wh

yawa3891 [41]

The total of the running backs' salaries need to be added together first. So, $1 000 000 + $850 000 + $750 000 + $500 000 = $3 100 000. Now we divide the total number of salaries by the running back salaries: $3 100 000/$33 000 000 = 0.094 x 100 = 9.4 %.
Round off to nearest percent = 9.00 %.

4 0

1 year ago