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sp2606 [1]
2 years ago
13

What is the simplified form of 3 StartRoot 135 EndRoot?

Mathematics
2 answers:
jek_recluse [69]2 years ago
5 0

Answer:

9 \sqrt{135}

Step-by-step explanation:

Express 135 as a product of 15 and 9:

135=15*9

So:

3\sqrt{15*9}

Now, use the following property:

\sqrt[n]{a*b} =\sqrt[n]{a}\hspace{3} \sqrt[n]{b}

Therefore:

3\sqrt{15} \sqrt{9}

Since the square root of 9 is 3, the simplified form of 3\sqrt{135}:

3\sqrt{15} \sqrt{9}=3*3\sqrt{15} =9\sqrt{15}

svetoff [14.1K]2 years ago
3 0

\bf 3\sqrt{135}~~ \begin{cases} 135=&3\cdot 3\cdot 15\\ &3^2\cdot 15 \end{cases}\implies 3\sqrt{3^2\cdot 15}\implies 9\sqrt{15}

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Answer:

<u>12.5% ≈ 13%</u>

Step-by-step explanation:

The rest of the question is: There are 75 pills in the batch.

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