48.25 x .20 = 9.65........................
Original price was $234.95
49% marked down = $234.95 *49 / 100 = $115.13
So now the sale price = original price - price of 49% marked down
sale price = $234.95 - $115.13 = $119.82
Answer: sale price of a DVD player having a red tag marked down by 49% should be $119.82
Answer:
4
Step-by-step explanation:
Here let the number of ride tickets be r, and the number of food tickets be f.
Hence

We first plot the two inequalities on graph as shown in attachment. From the graph we see that the two in-equation meet at (4,12)
Hence we can see that the maximum value of r is 4
<h2>
Answer:</h2>
The average speed of car is:
0.75 miles per minutes.
The equation of line is:

<h2>
Step-by-step solution:</h2>
The table that describes the time and number of miles marked is given by:
Time Miles
0 0
4 3
8 6
Clearly we could observe that with the increase in time by every 4 minutes the number of mile increases by 3.
i.e. the average speed is calculated as the ratio of change in miles to the change in time.
Hence,

Hence, the average speed=0.75 miles per minutes.
Also we will find the equation of the lines that related the miles and time by using the two-point formula.
i.e. any line passing through (a,b) and (c,d) is calculated by using the formula:

Here (a,b)=(0,0) and (c,d)=(4,3)
i.e. the equation is given by:
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)