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Tanzania [10]
2 years ago
14

Peaches are being sold for $2 per pound. If x represents the number of pounds of peaches bought and yrepresents the total cost o

f the peaches, which best describes the values of x and y?
Mathematics
2 answers:
Mila [183]2 years ago
7 0
1) x = pounds/peaches bought
2) y = total cost of the peaches
3) formula would be: y = $2x

but i don't understand what you'd want to know...
omeli [17]2 years ago
5 0

Let

x----------> represents the number of pounds of peaches bought

y----------> represents the total cost of the peaches

we know that

Peaches are being sold for 2\frac{\$}{pound}

so

the equation that best describes the values of x and y is equal to

y=2x or x=y/2

The relationship between the two variables, x, and y, represent a direct variation

therefore

<u>the answer is</u>

y=2x or  x=y/2

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5 Show different ways to make 492,623.
timama [110]

Step-by-step explanation:

Start by writing 492,623 in standard form

4 hundred thousands + 9 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones

We can write this in other ways by moving a digit to the next smaller place value.  For example, we move the 4 one place to the right to get 49 ten thousands:

49 ten thousands + 2 thousands + 6 hundreds + 2 tens + 3 ones

Then, we can move the 49 ten thousands to the right to get 492 thousands, and we can move 6 hundreds to the right to get 62 tens.

492 thousands + 62 tens + 3 ones

Or, we can do this:

4926 hundreds + 23 ones

6 0
2 years ago
An insurance company collected data from a class of high school sophomores on whether or not they have a cell phone and whether
NeX [460]

Answer:

C. Those who have a car tend to have a cell phone.

Step-by-step explanation:

The relative frequency for a data set n is calculated by dividing each frequency x_i by n.

We have a table that relates the use of cars and cell phones.

First, we take from the table the population that has a car.

n = 18

Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.

Then we calculate the relative frequencies f_{x_i} for those who have a cell phone and those who do not.

______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

 12/18                    6/18                     18

_______________________________________________

_______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

  0.666              0.333                   18

________________________________________________

Most students who have a car also have a cell phone.

Now we calculate the relative frequency for students who do not have a car.

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone       No cell phone             Total  n</em>

 2/7                     5/7                          7

_______________________________________________  

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone</em>      <em>  No</em> <em>cell phone           Total  n</em>

 0.286                 0.714                              7

_______________________________________________

Most students who do not have a car do not have a cell phone either.

<em>Then these data suggest that. Those who have a car tend to have a cell phone.</em>

Option C

6 0
2 years ago
Kenny buys mixed nuts at a corner market for $4.50 per pound. the cost is a function of the number of pounds of nuts bought. wha
Mila [183]

<span>A </span>continuous function<span> <span>allows the </span>x-values to be ANY points<span> in the interval, including fractions, decimals, and irrational values.</span> The graph is continuous because the cost could be any number depending on how many pounds of nuts Kenny bought in the market</span>

6 0
2 years ago
Read 2 more answers
Ryan invested some money in his bank he agreed a simple interest rate of 4% per annum for a 2 years At the end of the 2- years p
sdas [7]

\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$P\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &2 \end{cases} \\\\\\ I=P(0.04)(2)\implies I=0.08P\implies \stackrel{\textit{converting it to percentage}~\hfill }{0.08\cdot 100\implies 8\%\textit{ of original }P}

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