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Kisachek [45]
2 years ago
9

If a fish experiences an acceleration of 9.8 m/s^2 over a period of 1.4s (It must be falling), then what is its change in veloci

ty?
Mathematics
1 answer:
JulsSmile [24]2 years ago
6 0

Answer:

Change In velocity= 13.72 ms^-1

Step-by-step explanation:

fish experiences an acceleration of

9.8 m/s^2 over a period of 1.4s

Change in velocity/time= acceleration

Time in seconds= 1.4 s

Acceleration in meter per second square= 9.8 m/s^2

Change in velocity/time= acceleration

Change In velocity= acceleration*time

Change In velocity= 9.8*1.4(m/s^2 *s)

Change In velocity= 13.72 ms^-1

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For the answer to the question above,  the answer is simple, and it is -1 (because even powers of an imaginary number or i will always give a  -1).I hope my answer helped you with your problem. Have a nice day!
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The marketing manager of a branch office of a local telephone operating company wants to study the characteristics of residentia
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Answer:

No. There is not enough evidence to support the claim that the population standard deviation is different from $12.

Step-by-step explanation:

The null hypothesis is that the true standard deviation is 12.

The alternative hypothesis is that the true standard deviation differs from 12.

We can state:

H_0: \sigma=12\\\\H_a: \sigma\neq12

The significance level is 0.10.

The sample size is n=15, so the degrees of freedom are:

df=n-1=15-1=14

The sample standard deviation is 9.25.

The test statistic is

T=(n-1)(s/\sigma_0)^2=14*(9.25/12)^2=14*0.77^2=14*0.59=8.32

The critical values for rejecting the null hypothesis are:

\chi_{0.025,13}=5.00875\\\\\chi_{0.975,13}=24.7356

As T=8.32 is within the acceptance region (5.01, 24.74), the null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population standard deviation is different from $12.

8 0
1 year ago
What is the domain of the function shown in the table
Aleksandr [31]

we know that

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in this problem

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<u>the answer is the option B</u>

(-2,-1,0,1)

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In each represent the common form of each argument using letters to stand for component sentences, and fill in the blanks so tha
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Answer:

a

           a \to b

         \neg b

         \neg a

b

If  <u>all prime numbers are odd,</u> then <u>2 is  odd</u>.

2 is not odd.

Therefore, it is not the case that all prime numbers are odd.

Step-by-step explanation:

Considering part A

 The  first sentence is  

If all computer programs contain errors, then this program contains an error.

   The second sentence is

This program does not contain an error.

     The third  sentence is

Therefore, it is not the case that all computer programs contain errors.

Now we will use  a and  b  as the letter to denote the component sentences and   \neg a  and \neg b when the component sentences is not the case

So  a =  If all computer programs contain errors

and  

     b =  this program contains an error.

Generally then is represented as \to

Hence the first sentence is denoted as  

         a \to b

The  second sentence is represented as

            \neg b

The  third sentence is represented as

           \neg a

So part a can be represented as

      a \to b

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Considering part B

Here the objective is to fill in the blank spaces so that the logic of the sentence in part b is as that in part a

    Now comparing the second statement  a and  b

                "This program does not contain an error" = "2 is not odd" = \neg b

Hence      "this program contains an error." =  "2 is  odd" =  b

     Now comparing the third  statement  a and  b

Therefore, it is not the case that all computer programs contain errors.  

                                                =

     Therefore, it is not the case that all prime numbers are odd  

                                                =

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Hence

If all computer programs contain errors, = if all prime numbers are odd.= a                

             

             

3 0
1 year ago
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