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serg [7]
2 years ago
10

Lucia knows the fourth term in a sequence is 55 and the ninth term in the same sequence is 90. Explain how she can find the comm

on difference for the sequence. then use the common difference to find the second term of the sequence.
Mathematics
1 answer:
Andreyy892 years ago
4 0
Using the formula for the nth term of an arithmetic progression.
an = a + (n - 1)d
a(4) = a + 3d = 55
a(9) = a + 8d = 90
a(9) - a(4) => 5d = 35
d = 35/5 = 7.
From a(4): a = 55 - 3d = 55 - 3(7) = 55 - 21 = 34

a(2) = a + d = 34 + 7 = 41.

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Fill in the missing monomials: a 100x2= (_____)2
katrin2010 [14]

Answer:

100

Step-by-step explanation: its the same thing but in a different form

8 0
2 years ago
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At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.08 and the probability that the flight
notka56 [123]

Answer:

0.74

Step-by-step explanation:

Probability that it will rain: 8%

Probability that the flight will be delayed: 14%

Probability that it rains and the fight is delayed: 4%

8%+14%+4% =26%

so the answer is 74% or 0.74

5 0
2 years ago
Circular tracts of land with diameters 900 meters, 700 meters and 600 meters are tangent to each other externally. There are hou
Rudik [331]

Answer:

\alpha=69.28^o

\beta=61.26^o

\gamma=49.46^o

<em />A=227980.26\ m^2<em />

Step-by-step explanation:

<u>Triangle Solving</u>

If we had a triangle will its three sides of known length, we can solve for the rest of the parameters of the triangle, i.e. the area, perimeter and internal angles.

The three circles have diameters 900 m, 700 m and 600 m and are tangent to each other externally. The distances from their centers (where houses are located) are the sum of each pair of the radius of the circles. Thus, the sides of the triangle are

x=450+350=800

y=450+300=750

z=350+300=650

The internal angles can be computed by using the cosine's law

x^2=y^2+z^2-2yzcos\alpha

y^2=x^2+z^2-2xzcos\beta

z^2=x^2+y^2-2xycos\gamma

Where \alpha, \beta and \gamma are the opposite angles to x, y and z respectively. Solving for each one of them:

\displaystyle cos\alpha=\frac{y^2+z^2-x^2}{2yz}

\displaystyle cos\alpha=\frac{750^2+650^2-800^2}{2\cdot 750\cdot 650}

cos\alpha=0.3538

\alpha=69.28^o

Similarly

\displaystyle cos\beta=\frac{x^2+z^2-y^2}{2xz}

\displaystyle cos\beta=\frac{800^2+650^2-750^2}{2\cdot 800\cdot 650}

cos\beta=0.4808

\beta=61.26^o

The other angle is computed now

\displaystyle cos\gamma=\frac{x^2+y^2-z^2}{2xy}

\displaystyle cos\gamma=\frac{800^2+750^2-650^2}{2\cdot 800\cdot 750}

cos\gamma=0.65

\gamma=49.46^o

The area can be found by

\displaystyle A=\frac{1}{2}x.y.sin\gamma

\displaystyle A=\frac{1}{2}\cdot 800\cdot 750\cdot sin49.46^o

A=227980.26\ m^2

8 0
1 year ago
A guy wire is used to support flagpoles in windy areas. These wires are anchored in the ground to provide constant stability. Yo
r-ruslan [8.4K]

Answer: a) Length of wire to replace old one=9ft

b) Length of wire=3.09ft

Leftover wire=0.91ft

Step-by-step explanation: from the right angle triangle, Tan&=20/15

&=53.13°

Length of wire,x=cos 31.13=x/15

15cos31.13

X=9

b) Tan&=10/6

Tan^-110/6

&=59.05

Length= 6cos59.04

X=3.09

4-3.09=.91= leftover wire

8 0
1 year ago
Isabella can afford a $410-per-month car payment, and she's interested in either a sedan, which costs $21,600, or a station wago
mylen [45]

Answer:

isabella can afford neither the sedan nor the station wagon

Step-by-step explanation:

you read it and stop being a lazy

5 0
1 year ago
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