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ExtremeBDS [4]
2 years ago
8

prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x^2 + y^2 = 5, i ha

ve 3/5 marks and i tried with perpendicular gradient.

Mathematics
2 answers:
Brums [2.3K]2 years ago
8 0

Answer:

I dont even know

Step-by-step explanation:

too complicated

Kamila [148]2 years ago
5 0

Answer:

You have to use the discriminant b^2 -4ac =0 because lines that cut a circle only once are tangents.

Step-by-step explanation:

I think you can use the perpendicular gradient, but it'll be more tedious because then you'll have to prove that the line touching the circle is perpendicular to the line from the centre to the circle to the point of intersection. You'll have to form an equation using the coordinates of the centre of the circle and the point of intersection. You probably had a careless mistake/ calculation error in this process.

Instead, try

1. equating the line to the circle (which you did), then

2. let the coefficient of x^2 be a, the coefficient of x be b, and the constant terms be c.

3. simplify b^2-4ac

3. prove that b^2-4ac=0 because there is only one real and distinct root, hence there is only one point of intersection.

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Question 1(Multiple Choice Worth 1 points)
kirza4 [7]

Answer:


Step-by-step explanation:


1. 8 days

2. C?

3. A

4. B

5. C

6.D

7.48

8. A

9. 1.69%

10. False


I have no clue if these are right i tried my best to get them right, if they are wrong I am incredibly sorry!

- SavageSavvy

5 0
1 year ago
Write an exponential function in the form y<br> and (3,72).<br> ab" that goes through points (0,9)
Vikentia [17]

Answer:

y=9 ( {2}^{x} )

Step-by-step explanation:

Let the exponential function be

y = a {b}^{x}

We substitute (0,9) to get:

9 = a {b}^{0}

9 = a(1)

a = 9

The equation now becomes:

y = 9 {b}^{x}

We substitute (3,72) to get:

72 =9  {b}^{3}

8={b}^{3}  \\  {2}^{3}  =  {b}^{3}

b = 2

The equation is therefore

y=9 ( {2}^{x} )

3 0
2 years ago
A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
1 year ago
A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height
hichkok12 [17]

Answer:

\frac{1}{3} ft/min is the rate of changing of width

Step-by-step explanation:

Given -

The area always remain constant i.2 2 square feet.

Height of the rectangle = 2 feet

Rate of changing of height = 6 feet per minute

Since area is constant

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = \frac{1}{3} ft/min

4 0
1 year ago
Clarissa's income puts her in the bottom tax bracket (10%) last year. During the same year, she earned $250 in dividends and $75
Art [367]

Answer:

75 in coupons.

250 in dividends.

profit of 600 - 425 = 175 from her stock investment.  

her total income is 250 + 75 + 175 = 500.  

if all of this is taxed at 10%, then her tax will be 500 * .1 = 50.  

8 0
1 year ago
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