Angle ABD measures (4x + 10)o. Angle ACD measures (5x − 2)o.

Mathematics

2 answers:

melamori03 [73]2 years ago

7 0

Answer:

96°

Step-by-step explanation:

natta225 [31]2 years ago

4 0

Answer: 116°

Step-by-step explanation:

You might be interested in

Two square rooms have a total floor area of 89m2. One room is 3m longer each way than the other. Find the dimensions of the two

Rudiy27

Answer:

Step-by-step explanation:

Let the smaller room have an area of x^2

Let the larger room have an area of (x + 3)^2

(x+3) ^2 + x^2 = 89 Be careful not to make it 89^2.

x^2 + 6x + 9 + x^2 = 89 Expand the binomial squared

2x^2 + 6x + 9 - 89 = 0 Subtract 89 from both sides

2x^2 + 6x + 9 - 89 = 0 Combine

2x^2 + 6x - 90=0 Divide by 2

x^2 + 3x - 45 = 0 This factors.

(x + 9)(x- 5) = 0

X + 9 gives nothing useful

x - 5 = 0

x = 5

x + 3 = 5+3 = 8

So the answer is A

3 0

2 years ago

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores o

otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So $X = 52, \mu = 70, \sigma = 11$