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aleksandrvk [35]
2 years ago
14

The midpoint of JK is point L at (–1, 8). One endpoint is J(4, –15). Which equations can be solved to determine the coordinates

of the other endpoint, K? Check all that apply.  = –1  = 4 –15 + y1 = 4 –15 + y1 = 16  = x1 = y1
Mathematics
2 answers:
ycow [4]2 years ago
6 0
Given two endpoints: (x_1,\ y_1) and (x_2,\ y_2), the midpoint of the two endpoints (x_m,\ y_m) is given by
(x_m,\ y_m)=\left( \frac{x_1+x_2}{2} ,\  \frac{y_1+y_2}{2}\right)

Thus, given the midpoint L(-1, 8) and one endpoint J(4, -15). The second endpont is given by
(-1,\ 8)=\left( \frac{x_1+4}{2} ,\ \frac{y_1+(-15)}{2}\right)
i.e.
\frac{x_1+4}{2} =-1 \\  \\ x_1+4=-2 \\  \\ x_1=-2-4=-6
and
\frac{y_1+(-15)}{2}=8 \\  \\ y_1-15=16 \\  \\ y_1=16+15=31
Grace [21]2 years ago
4 0

A and D

............................................

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Find f. f ''(x) = −2 + 36x − 12x2, f(0) = 8, f '(0) = 18 f(x) =
Alik [6]
Integrate <span>f ''(x) = −2 + 36x − 12x2 with respect to x:

f '(x) = -2x + (36/2)x^2 - (12/3)x^3 + c.  Find c by letting x = 0 and using f(0)=8.

Then f '(0) = -2x + 18x^2 - 4x^3 + c = 18 (which was given).

Then             -0      + 0      - 0 + c = 18, so c = 18 and 

f '(x) = </span>-2x + 18x^2 - 4x^3 + 18.

Go through the same integration process to find f(x).
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2 years ago
Millie has a box of 1 hundred cubes. She also has a bag of 70 cubes. How many trains of 10 cubes can she make?
ANTONII [103]
She has a total of 170 cubes

170/10=17 trains
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What are the solution(s) of x squared minus 4 = 0? x = negative 4 or x = 4 x = negative 2 or x = 2 x = 2 x = 4
frosja888 [35]

Answer:

Step-by-step explanation:

The expression is

x^2 - 4

This is a quadratic expression.

To find the solution, we will equate the the expression to zero. It becomes

x^2 - 4 = 0

Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.

x^2 - 4 + 4 = 0 + 4

x^2 = 4

Take square root of the right hand side of the equation and left hand side of the equation. It becomes

√x^2 = √4

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7 0
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A cup of coffee has approximately 310 mg of caffeine. Each hour, the caffeine in your system decreases by about 35%. How much ca
Alex787 [66]

Answer:

∴35.97 mg caffeine would be left in the system after 5 hours.

Step-by-step explanation:

Given that,

A cup of coffee has approximately 310 mg of caffeine.

Caffeine decrease at a rate 35% per hour.

Exponential Function:

y(t)=y_0(1-r)^t

y(t)= Amount caffeine after t hours

y_0= Initial amount of caffeine

r= rate of decrease

t = Time in hour.

Here y(t)=?, y_0 = 310 mg, r=35%=0.35, t= 5 hours

y(t)=310(1-0.35)^5

      =35.97 mg

∴35.97 mg caffeine would be left in the system after 5 hours.

3 0
2 years ago
Which product is modeled by the number line below?
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Answer:

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Step-by-step explanation:

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