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aleksandrvk [35]
2 years ago
14

The midpoint of JK is point L at (–1, 8). One endpoint is J(4, –15). Which equations can be solved to determine the coordinates

of the other endpoint, K? Check all that apply.  = –1  = 4 –15 + y1 = 4 –15 + y1 = 16  = x1 = y1
Mathematics
2 answers:
ycow [4]2 years ago
6 0
Given two endpoints: (x_1,\ y_1) and (x_2,\ y_2), the midpoint of the two endpoints (x_m,\ y_m) is given by
(x_m,\ y_m)=\left( \frac{x_1+x_2}{2} ,\  \frac{y_1+y_2}{2}\right)

Thus, given the midpoint L(-1, 8) and one endpoint J(4, -15). The second endpont is given by
(-1,\ 8)=\left( \frac{x_1+4}{2} ,\ \frac{y_1+(-15)}{2}\right)
i.e.
\frac{x_1+4}{2} =-1 \\  \\ x_1+4=-2 \\  \\ x_1=-2-4=-6
and
\frac{y_1+(-15)}{2}=8 \\  \\ y_1-15=16 \\  \\ y_1=16+15=31
Grace [21]2 years ago
4 0

A and D

............................................

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your friend deposits $9500 in an investment account that earns 2.1% annual interest. what is the balance after 11 years when the
solmaris [256]

Answer:

The answer is "$ 11,961.43"

Step-by-step explanation:

Given values:

P =  $ 9500

r= 2.1 %

time (t)= 11 year

total quarterly year =4

Formula:

A= P (1+\frac{r}{n})^{nt}\\\\

quarterly time = 4 \times 11

                         = 44

A= P (1+\frac{r}{n})^{nt}\\\\

A = 9500 ( 1+ \frac{0.021}{4})^{44}\\\\A = 9500(\frac{4+ 0.021}{4} )^{44} \\\\A = 9500(\frac{4.021}{4} )^{44} \\\\A= 9500 (1.00525)^{44}\\\\A= 9500(1.25909819)\\\\A= 11,961. 43\\

8 0
2 years ago
Divide 42 in a ratio of 1:2:3
Vilka [71]

the ratio in which 42 should be divided is 1:2:3

the sum of the parts of the ratio is - 1 + 2 + 3 = 6

this means that there's a sum of 6 parts

so we need to find how much 1 part is equivalent to

if 6 parts are equivalent to 42

then 1 part is equivalent to - 42/6 = 7

so the ratio should be 1:2:3

1 part - 7

2 parts - 7 x 2 = 14

3 parts - 7 x 3 = 21

therefore 42 divided into 1:2:3 ratio is as follows

7 : 14 : 12

4 0
2 years ago
Read 2 more answers
A California distributor of sporting equipment expects to sell 10,000 cases of tennis balls during the coming year at a steady r
sleet_krkn [62]

Economic Order Quantity

The economic order quantity, that is, the order quantity that minimizes the inventory cost is:

300 cases of tennis balls

Data and Calculations:

Sales of tennis balls for the coming year = 10,000 units

Carrying (holding) costs per case = $10

Cost of placing orders with the manufacturer = $45 per order

Economic Order Quantity (EOQ) = square root of (2 * Annual Demand/Sales * Ordering cost)/Carrying cost per case

= square root of (2 * 10,000 * $45)/$10

= square root of 90,000

= 300 tennis balls

This implies that the distributor will place about 33 orders in the coming year.  With each order, the quantity placed is 300 units.  This is the economic order quantity that will minimize its inventory cost for the year.

8 0
2 years ago
=
SOVA2 [1]

Answer:

Tn=13n-18

Step-by-step explanation:

Tn=-5(n-1)13

Simplify

this is using the a+(n-1)d

8 0
2 years ago
Read 2 more answers
Maura writes an expression equivalent to 8a - (-3 - 5a) - 2a. Her work is in the picture. In what step does Maura make a mistake
NISA [10]

Answer:

11a + 3

Step-by-step explanation:

Step 1 : 8a + 3 - 5a - 2a

error => - 5a

8a - (- 3 - 5a) - 2a =

= 8a + 3 + 5a - 2a

= (8a + 5a - 2a) + 3

= 11a + 3

7 0
2 years ago
Read 2 more answers
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